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3 years ago

Find the sum of the three expressions and choose the correct answer.

Mathematics

2 answers:

riadik2000 [5.3K]3 years ago

7 0

Answer:

Sum of -8a³b+3a²b²-5,2+5a²b² and 3a³b+7-9a²b² is:

-5a³b-a²b²+4

Step-by-step explanation:

We have to find the sum of:

-8a³b+3a²b²-5,2+5a²b² and 3a³b+7-9a²b²

-8a³b+3a²b²-5+2+5a²b²+3a³b+7-9a²b²

= -5a³b-a²b²+4

Hence, sum of -8a³b+3a²b²-5,2+5a²b² and 3a³b+7-9a²b² is:

-5a³b-a²b²+4

cupoosta [38]3 years ago

6 0

-8a^3 b + 3a^2 b^2 - 5 + 2 + 5a^2 b^2 + 3a^3 b + 7 - 9a^2 b^2
= -5a^3 b - a^2 b^2 + 4

answer is

C.) -5a3b - a2b2 + 4

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The area of triangle ABC is 3√2 square inches. Find the measure of the acute angle, A, if b = 9 meters and c = 2 meters.

taurus [48]

Answer:

$A\approx 28^{\circ}$

Step-by-step explanation:

Please find the attachment.

We have been given that area of triangle ABC is 3√2 square inches.

$\text{Area}=\frac{1}{2}\text{Base}\times \text{height}$

We know that area of triangle an be found using trigonometry as:

$\text{Area}=\frac{1}{2}\times c\times h$

$\text{sin}(A)=\frac{h}{9}\\h=9\cdot \text{sin}(A)$

$3\sqrt{2}=\frac{1}{2}\times 2\times 9\cdot \text{sin}(A)$

$3\sqrt{2}=9\cdot \text{sin}(A)$

$9\cdot \text{sin}(A)=3\sqrt{2}$

$\text{sin}(A)=\frac{3\sqrt{2}}{9}$

$\text{sin}(A)=\frac{\sqrt{2}}{3}$

Now, we will use inverse sine to find the value of angle A as:

$A=\text{sin}^{-1}(\frac{\sqrt{2}}{3})$

$A=28.1255057^{\circ}$

$A\approx 28^{\circ}$

Therefore, the measure of angle A is approximately 28 degrees.

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3 years ago

A wooden rod of 5 m 75 cm was cut into 5 equal pieces. What is the length of each piece.

hram777 [196]

We have: 5m 75cm = 5.75 m

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ok done. Thank to me :>

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2 years ago

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uranmaximum [27]

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3 years ago

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sp2606 [1]

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3 years ago

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lutik1710 [3]

Answer:

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Step-by-step explanation:

first term = 4

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so,

46th term = 4 + ( 45 ) × 8
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i hope it helped....

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3 years ago