Let ‘s’ be the son’s age 12 years ago.
Let ‘f’ be the father’s current age.
4 years ago, the son was:
s-4
So, his father is currently:
3(s-4)
=
3s-12
Therefore:
f = 3s-12
In twelve years, the son will be:
s+12
And the father will be:
f+12
This can also be written as:
3s-12+12 as the fathers younger age would be f = 3s+12
=
3s
So, we know that s+12 is half the fathers current age, meaning the father is currently 2(s+12) which is equivalent to 2s+24. Also, we know that the father is currently 3 times the sons age 12 years ago, so 3s (proven by the calculations we made above). Therefore, 2s+24=3s which means 24=s. We can then substitute this, and we will receive 24+12 = 36
Son’s current age: 36
We then substitute the son’s age 12 years ago into 2s+24 to give us the father’s age.
2(24)+24 = 72
Father’s current age: 72
X=12.5
If the perimeter is 90
90=3x+3x+15
Combine like terms
90=6x+15
Subtracts 15 from both sides
75=6x
Divide by six to get x by itself
12.5=x
Does this help?
Answer:
Step-by-step explanation:
−6x+6−7=2x+8
-1-8=2x+6x
8x=-9
x= -
Answer:
30 and 35
Step-by-step explanation:
Put this question into equation form:
Let x be the smaller number, if the larger number is 5 more and the total is 65:
x + 5 + x = 65
2x + 5 = 65
Subtract 5 from both sides
2x + 5 - 5 = 65 - 5
2x = 60
Divide both sides by 2:
2x ÷ 2 = 60 ÷ 2
x = 30
As the larger number is 5 bigger:
30 + 5 = 35
So the two numbers are 30 and 35.
Hope this helps!
Step-by-step explanation:
2×750=1500 + 0^7. ( 0×0×0×0×0×0×0=0)
So,
1500 Answer
