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3 years ago

Is the square root of 42 rational or irrational? Explain

Mathematics

1 answer:

MA_775_DIABLO [31]3 years ago

5 0

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Hi there!

~

$\sqrt{42}$ ≈ $6.4807406984087...$

So $\sqrt{42}$ is irrational (since the decimal portion doesn't terminate or repeat)

❀Hope this helped you!❀

☽------------❀-------------☾

(The other person copied there answer from google!)

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A rectangle has a length of 20 inches. if its perimeter is 64 inches, what is the area?

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Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf 240 \: {inches}^{2} }}}}$

Step-by-step explanation:

Given,

Length of a rectangle = 20 inches

Perimeter of a rectangle = 64 inches

Area of a rectangle = ?

Let width of a rectangle be ' w ' .

First, finding the width of a rectangle

$\boxed{ \sf{perimeter = 2(l + w)}}$

plug the values

⇒ $\sf{64 = 2(20 + w)}$

Distribute 2 through the parentheses

⇒ $\sf{64 = 40 + 2w}$

Swap the sides of the equation

⇒ $\sf{40 + 2w = 64}$

Move 2w to right hand side and change it's sign

⇒ $\sf{2w = 64 - 40}$

Subtract 40 from 64

⇒ $\sf{2w = 24}$

Divide both sides of the equation by 2

⇒ $\sf{ \frac{2w}{2} = \frac{24}{2} }$

Calculate

⇒ $\sf{w = 12 \: inches}$

Width of a rectangle ( w ) = 12 inches

Now, finding the area of a rectangle having length of 20 inches and width of 12 inches

$\boxed{ \sf{area \: of \: rectangle = length \: \times \: \: width}}$

plug the values

⇒ $\sf{area \: of \: rectangle =20 \times 12 }$

Multiply the numbers : 20 and 12

⇒ $\sf{area \: of \: rectangle = 240 \: {inches}^{2} }$

Hence, Area of a rectangle = 240 inches²

Hope I helped !

Best regards!

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