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3 years ago

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A certain ceiling is made up of tiles. Every square meter of ceiling requires 10.75 tiles. Fill in the table with the missing va

lues. What is the value of the red X?

2 answers:

egoroff_w [7]3 years ago

7 0

Answer:

107.5

Step-by-step explanation:

ANEK [815]3 years ago

5 0

Answer:

See Explanation

Step-by-step explanation:

Given:

See Attachment

Required

Complete the table

From the question, we understand that:

$1m^2 = 10.75\ tiles$

So:

When square meters = 1

$X = 10.75 * 1$

$X = 10.75$

When square meters = 10

$X = 10.75 * 10$

$X = 107.5$

Assume any value of square meter for the third row;

Say: square meters = 20

$X = 10.75 * 20$

$X = 215$

When square meters = a

$X = 10.75 * a$

<h2> $X = 10.75a$ </h2>

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Choose 5 cards from a full deck of 52 cards with 13values (2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K, A) and 4 kinds(spade, diamond, h

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Answer:

a) 182 possible ways.

b) 5148 possible ways.

c) 1378 possible ways.

d) 2899 possible ways.

Step-by-step explanation:

The order in which the cards are chosen is not important, which means that we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question, we have that:

There are 52 total cards, of which:

13 are spades.

13 are diamonds.

13 are hearts.

13 are clubs.

(a)Two-pairs: Two pairs plus another card of a different value, for example:

2 pairs of 2 from sets os 13.

1 other card, from a set of 26(whichever two cards were not chosen above). So

$T = 2C_{13,2} + C_{26,1} = 2*\frac{13!}{2!11!} + \frac{26!}{1!25!} = 182$

So 182 possible ways.

(b)Flush: five cards of the same suit but different values, for example:

4 combinations of 5 from a set of 13(can be all spades, all diamonds, and hearts or all clubs). So

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(c)Full house: A three of a kind and a pair, for example:

4 combinations of 3 from a set of 13(three of a kind ,c an be all possible kinds).

3 combinations of 2 from a set of 13(the pair, cant be the kind chosen for the trio, so 3 combinations). So

$T = 4*C_{13,3} + 3*C_{13.2} = 4*\frac{13!}{3!10!} + 3*\frac{13!}{2!11!} = 1378$

So 1378 possible ways.

(d)Four of a kind: Four cards of the same value, for example:

4 combinations of 4 from a set of 13(four of a kind, can be all spades, all diamonds, and hearts or all clubs).

1 from the remaining 39(do not involve the kind chosen above). So

$T = 4*C_{13,4} + C_{39,1} = 4*\frac{13!}{4!9!} + \frac{39!}{1!38!} = 2899$

So 2899 possible ways.

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3 years ago

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we know that

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This inequality represent Jeanne’s possible number of hours worked this week

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see the attached figure N $1$

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see the attached figure N $2$

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$6x+10y \geq 75$ --------> inequality $2$

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Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

The given expression will be rearranged as below:-

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Solve the above expression for the value of y and the x variable will become independent.

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