ANSWER
True
EXPLANATION
The given trigonometric equation is:

We take the LHS and simplify to arrive at the RHS.

Collect LCM on the right hand side to get;

This implies that



This identity has been verified .Therefore the correct answer is true.
Answer:
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Answer: Where are the lines?
We must follow order of operations rules (PEMDAS) here: exponentiation first, followed by multiplication and division, followed by addition and subtraction.
Thus, -2^2-3(-2)+1 becomes:
-[4] + 6 + 1 = 2 + 1 = 3 (answer)