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scZoUnD [109]
2 years ago
11

Ami'yan runs every day for exercise at a rate of 1 kilometer every 15 minutes. How many meters does he run in 1 hour? - Thank yo

u in advance
Mathematics
1 answer:
Alona [7]2 years ago
6 0

Answer:

The total distance covered in 1 hour  is 4000 meters.

Step-by-step explanation:

The distance Ami'yan runs is 15 minutes = 1 kilometer

Using the unit formula,

The distance ran in 1 minute = (\frac{1}{15} ) \textrm{Kilometer}

Now, 1 hour = 60 minutes

⇒The distance covered in 60 minutes =  60 x (Distance run in 1 minute)

                                                               = 60 \times \frac{1}{15}    = 4

So, the distance covered in 1 hour  = 4 kilometer

1 kilometer = 1000 meters

⇒ 4 km =  4 x 1000 meters = 4000 m

Hence, the total distance covered in 1 hour  = 4000 meters.

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hichkok12 [17]

Answer:

Area: 201.06

Circumference:50.26

Step-by-step explanation:

Area of a circle: pi*r^2

8^2=8*8=64

64*pi=201.06193 Rounded to the neares hundredth=201.06

_________________________________________________

Circumference of a circle: 2pi * r

2*8=16

16*pi=50.2654825 Rounded to the nearest hundredth = 50.26

4 0
2 years ago
The Gomez family just purchased a $2,574.54 laptop computer. They made a down payment of $574.54. Through the store's installmen
Maurinko [17]
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  $2,574.54 -574.54 = $2000.00

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3 0
3 years ago
A tourist looks out from the observation deck of the Space Needle in Seattle. The deck is at a height of 520 ft. She sees her fr
evablogger [386]

Answer:

40 feet

Step-by-step explanation:

Given : The deck is at a height of 520 ft. She sees her friend on the ground below at an angle of depression of 85.6 degrees.

To Find : What is the distance between the two? Round your answer to the nearest tenth of a foot.

Solution :

Refer the attached figure

Height of deck =AB =520 ft.

Angle of depression ∠C = 85.6°

We are supposed to find length of BC i.e. distance between two.

We will use trigonometric ratios :

tan \theta = \frac{perpendicular}{base}

tan 85.6^{\circ} = \frac{AB}{BC}

12.99615= \frac{520}{BC}

BC= \frac{520}{12.99615}

BC= 40

Thus the distance between two is 40 feet


7 0
2 years ago
Read 2 more answers
Find the value of the variable such that: the value of 5−a is 20 greater than the value of 6a−1
vovangra [49]

Answer:

-2

Step-by-step explanation:

(5 - a) = 20 + (6a -1) . . . . . 5-a is 20 greater than 6a-1

5 = 7a +19 . . . . . . . . . . . . . add a, collect terms

-14 = 7a . . . . . . . . . . . . . . . subtract 19

-2 = a . . . . . . . . . . . . . . . . divide by 7

The value of the variable is -2.

_____

<u>Check</u>

5 - (-2) = 7

6(-2) -1 = -13

7 is 20 greater than -13, so the answer checks OK.

4 0
3 years ago
Which equations describes the line shown?
LenKa [72]
It should be y=2x-3 since it’s touching -3 on the y axis and the it’s going 2 units up and 1 to the right, making the slope = 2.
3 0
1 year ago
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