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scZoUnD [109]
3 years ago
11

Ami'yan runs every day for exercise at a rate of 1 kilometer every 15 minutes. How many meters does he run in 1 hour? - Thank yo

u in advance
Mathematics
1 answer:
Alona [7]3 years ago
6 0

Answer:

The total distance covered in 1 hour  is 4000 meters.

Step-by-step explanation:

The distance Ami'yan runs is 15 minutes = 1 kilometer

Using the unit formula,

The distance ran in 1 minute = (\frac{1}{15} ) \textrm{Kilometer}

Now, 1 hour = 60 minutes

⇒The distance covered in 60 minutes =  60 x (Distance run in 1 minute)

                                                               = 60 \times \frac{1}{15}    = 4

So, the distance covered in 1 hour  = 4 kilometer

1 kilometer = 1000 meters

⇒ 4 km =  4 x 1000 meters = 4000 m

Hence, the total distance covered in 1 hour  = 4000 meters.

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What is 3/4 ÷ 1/6? Please help !......
Reika [66]

Answer:

4 1/2

Step-by-step explanation:

Apply the fractions formula for division, to

3/4÷1/6

and solve

3/6x4/1

=18/4

Reduce by dividing both the numerator and denominator by the Greatest Common Factor GCF(18,4) = 2

18/24÷2/2=9/2

Convert to a mixed number using

long division for 9 ÷ 2 = 4R1, so

9/2=4 1/2

Therefore:

3/4÷1/6=4 1/2

4 0
3 years ago
3 • (4 + 5) is how much more than 3 • 4 + 5 ?
IrinaK [193]

Answer:27

Step-by-step explanation:

8 0
3 years ago
Its
damaskus [11]

Answer:

P(Green\ and\ Green) = \frac{25}{144}

Step-by-step explanation:

Given

Green=5

Blue = 7

Required

P(Green\ and\ Green)

This is calculated as:

P(Green\ and\ Green) = P(Green) * P(Green)

Since, it is a probability with replacement, we have:

P(Green\ and\ Green) = \frac{Green}{Total} * \frac{Green}{Total}

So, we have:

P(Green\ and\ Green) = \frac{5}{12} * \frac{5}{12}

P(Green\ and\ Green) = \frac{25}{144}

5 0
3 years ago
I need help Please help.
asambeis [7]

Answer:

Step-by-step explanation:

Number of students 10

Problem 1. $625 for the bus hire per friday, So 625*4=$2500

Problem 2. 2500/25=$100 each for the whole 4 weeks

Problem 3.

10 students tickets 220= 2200 for all tickets. The bus, 625/10 = $62.5*4= $250 dollars for the whole 4 weeks for the bus so in all each student pays $470 each

20 students, tickets 220=4400 for all tickets. The bus, 625/20=$31.25*4=$125 for the whole 4 weeks for the bus, so in all each student must pay $345 each

30 students, tickets 220 = 6600 for all tickets. The bus, 625/30 =$20.83*4=$83.32 for the whole 4 weeks for the bus, so in all each student must pay $303.32 each

41 students, tickets $160=$6560 for all tickets. The bus, because you need 2 buses at 625 each so $1250 for both buses 1250/41= 30.49*4=$121.96 for the whole 4 weeks for the bus. So in al each student must pay $281.96 each

Hope this is correct

8 0
3 years ago
Please help right away
andrew-mc [135]

Answer:

100

Step-by-step explanation:

Mixed candy question... Skittles jar... to be filled with Jelly beans.

Let's first calculate the volume of the jar.  We'll assume it's a regular cylindrical prism jar, unlike the one on the photo which is narrower on top.

V = π * r² * h = π * (3.5)² * 11.5 = 140.875 π = 442.6 cubic cm

Now, we don't have the precise measurement of a jelly bean, but we know it's roughly 2-3 cubic cm.  The precision isn't needed to answer this question, just to have a rough idea... it's no 300 cu cm per jelly bean.

So, let's assume a 3 cu cm per jelly bean (2 cu cm wouldn't the final answer)....

442.6 / 3 = 147.5 jelly beans, approximately.

So, can they fit 100,000?  No

Can we fit 10,000 in there?  No

Can we fit 100?  Yes.

Can we fit 1?  Certainly

The most reasonable lower-limit would then be 100.

4 0
3 years ago
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