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3 years ago

13

A mountaineer descends a mountain for 5 hours. On average, she climbs down 500 feet each hour. What is her change in elevation a

fter 5 hours?

1 answer:

jenyasd209 [6]3 years ago

3 0

Answer:

2500 feet

Step-by-step explanation:

500*5=2500

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vlabodo [156]

The correct answer is 673
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3 years ago

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RUDIKE [14]

Answer:

i got 38

Step-by-step explanation:

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3 years ago

A survey of 1 comma 558 randomly selected adults showed that 522 of them have heard of a new electronic reader. The accompanying

sineoko [7]

Answer with explanation:

Let p be the proportion of adults have heard of the new electronic reader.

Given claim : The accompanying technology display results from a test of the claim that 38% of adults have heard of the new electronic reader.

i.e. $p=0.38$

Then , the set of hypothesis will be :-

$H_0: p=0.38\\\\H_a:p\neq0.38$

Since, the alternative hypothesis is two tailed , so the test is two-tailed test.

Also, it is given that the sample size : $n=1558$

Number of adults showed that they have heard of a new electronic reader=522

So the sample proportion for adults have heard of the new electronic reader : $\hat{p}=\dfrac{522}{1558}\approx0.34$

The test statistic for proportion is given by :-

$z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\\\\Rightarrow\ z=\dfrac{0.34-0.38}{\sqrt{\dfrac{0.38(1-0.38)}{1558}}}\\\\\\\Rightarrow\ z=-3.25279036541\approx-3.25$

By using standard normal distribution table , the P-value for two tailed test corresponds to the obtained z-value = $=0.0011541$

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3 years ago

A circle cuts the x-axis at (4,0) and (14,0), and cuts the y-axis at (0,6) and (0,8). Find it's equation

gayaneshka [121]

It is not a circle but you can find the equation of the ellipse.
To do this we need to work out the major and minor radii and the centre
The centre is at (9, 7)
The major (y) radius is 1 and the minor (x) radius is 5
Therefore the equation is (x-9)/5 + (y-7)/1 = 1

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3 years ago

A^-1/[a^-1 - b^-1] + a^-1/[a^-1 + b^-1]

o-na [289]

$\dfrac{a^{-1}}{a^{-1}-b^{-1}}+\dfrac{a^{-1}}{a^{-1}+b^{-1}}=a^{-1}\left(\dfrac{a^{-1}+b^{-1}}{(a^{-1}-b^{-1})(a^{-1}+b^{-1})}+\dfrac{a^{-1}-b^{-1}}{(a^{-1}+b^{-1})(a^{-1}-b^{-1})}\right)$

$=a^{-1}\left(\dfrac{(a^{-1}+b^{-1})+(a^{-1}-b^{-1})}{a^{-2}-b^{-2}}\right)$

$=\dfrac{2a^{-2}}{a^{-2}-b^{-2}}$

$=\dfrac{2b^2}{b^2-a^2}$

5 0

3 years ago

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