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Valentin [98]
3 years ago
14

The equatorial diameter of a model of earth is 25.6 cm. What is the total surface area of the model​

Mathematics
1 answer:
Arisa [49]3 years ago
7 0

Answer:

2059.7\,\,cm^2

Step-by-step explanation:

Diameter of a model of earth (D) = 25.6 cm

Radius of a model of earth (r) = \frac{D}{2}=\frac{25.6}{2}=12.8\,\,cm

Earth has the shape of a sphere.

Total surface area of a sphere = 4\pi r^2

Put \pi=\frac{22}{7}\,,\,r=12.8\,\,cm

So,

Total surface area of the model =4(\frac{22}{7})(12.8)^2=2059.7\,\,cm^2

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JulsSmile [24]

Given:

A figure of a rectangular prism with length l, width w and height h.

To find:

The surface area of the rectangular prism.

Solution:

The product of twice of the length l and the width w is:

2\times l\times w=2lw          ...(i)

The product of twice of the length l and the height is:

2\times l\times h=2lh           ...(ii)

The product of twice of the width w and the height h is:

2\times w\times h=2wh       ...(iii)

The surface area of the prism is the sum of (i), (ii) and (iii). So, the expression for the surface area is:

A=2lw+2lh+2wh

A=2(lw+lh+wh)

Therefore, the required expression is 2(lw+lh+wh).

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klemol [59]

Answer:

I do not understand ummmm

8 0
3 years ago
Please help me im stuck
dmitriy555 [2]

Answer:

a = -0.5

Step-by-step explanation:

\rm Solve  \: for  \: a: \\  \rm \longrightarrow - \dfrac{1}{4}a  - 4 =  \dfrac{7}{4}a  - 3 \\   \\  \rm Put \:  each  \: term \:  in  \: - \dfrac{1}{4}a  - 4  \:  over \:  the \\ \rm  common  \: denominator  \: 4: \\ \rm - \dfrac{a}{4}  - 4  = - \dfrac{a}{4}  -  \dfrac{16}{4} :  \\ \rm \longrightarrow  - \dfrac{a}{4}  -  \dfrac{16}{4}  = \dfrac{7}{4}a  - 3 \\  \\  \rm  - \dfrac{a}{4}  -  \dfrac{16}{4}  = \dfrac{ - a - 16}{4}  : \\  \rm \longrightarrow  \dfrac{ - a - 16}{4} = \dfrac{7}{4}a  - 3  \\  \\ \rm Put  \: each  \: term \:  in \: \dfrac{7}{4}a  - 3   \:  over  \: the  \\ \rm common \:  denominator \:  4: \\  \rm  \dfrac{7a}{4}  - 3  =  \dfrac{7a}{4} -  \dfrac{12}{4} : \\   \rm \longrightarrow  \dfrac{ - a - 16}{4} = \dfrac{7a}{4}  -  \dfrac{12}{4}  \\  \\  \rm  \dfrac{7a}{4} -  \dfrac{12}{4}  =  \frac{7a - 12}{4} : \\  \rm \longrightarrow  \dfrac{ - a - 16}{4} = \dfrac{7a - 12}{4}   \\  \\  \rm Multiply  \: both  \: sides  \: by \:  4:  \\ \rm \longrightarrow  \dfrac{ - a - 16}{ \cancel{4}}  \times  \cancel{4}= \dfrac{7a - 12}{ \cancel{4}}  \times  \cancel{4} \\  \\  \rm \longrightarrow -a - 16 = 7 a - 12 \\  \\  \rm Subtract \:  7 a  \: from \:  both  \: sides: \\  \rm \longrightarrow (-a - 7 a) - 16 = (7 a - 7 a) - 12 \\  \\  \rm -a - 7 a = -8 a: \\  \rm \longrightarrow -8 a - 16 = (7 a - 7 a) - 12 \\  \\  \rm 7 a - 7 a = 0: \\  \rm \longrightarrow -8 a - 16 = -12 \\  \\  \rm Add \:  16 \:  to \:  both  \: sides: \\  \rm \longrightarrow (16 - 16) - 8 a = 16 - 12 \\  \\  \rm 16 - 16 = 0: \\  \rm \longrightarrow -8 a = 16 - 12 \\  \\  \rm 16 - 12 = 4: \\  \rm \longrightarrow -8 a = 4 \\  \\  \rm Divide \:  both \:  sides \:  of \:  -8 a = 4  \: by \:  -8: \\  \rm \longrightarrow  \dfrac{ - 8a}{ - 8}  =  \dfrac{4}{ - 8}  \\  \\  \rm  \dfrac{ - 8}{ - 8}  = 1: \\  \rm \longrightarrow a =   - \dfrac{4}{  8}  \\  \\  \rm   - \dfrac{4}{  8}  =  -  \dfrac{1}{2}  :  \\   \rm \longrightarrow a =  -  \dfrac{1}{2}  \\  \\  \rm \longrightarrow a =  - 0.5

6 0
3 years ago
WILL GIVE BRAINLIEST
Mnenie [13.5K]

Answer:

C

Step-by-step explanation:

Given the 2 equations

3x + 4y = 8 → (1)

y - 5x = 2 ← rewrite as

- 5x + y = 2 → (2)

Multiplying (2) by - 4 and adding to (1) will eliminate the y- term

20x - 4y = - 8 → (3)

Add (1) and (3) term by term to eliminate y

23x + 0 = 0

23x = 0 , then

x = 0

Substitute x = 0 into either of the 2 equations and solve for y

Substituting into (1)

3(0) + 4y = 8

4y = 8 ( divide both sides by 4 )

y = 2

solution is (0, 2 )

That is the lines intersect once at (0, 2 )

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3 years ago
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Since 360 is a full loop around the circle, the points end up in the exact same place.

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3 years ago
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