Answer:
The length for the 97th percentile for a man's arm span is 74.96 inches.
Step-by-step explanation:
We have a normal distribution for men's arm span, with mean of 68 inches and standard deviation of 3.7 inches.
The 97th percentil represents the value for which 97% of the observations are below.
We can search for the 97th percentile for the standard normal distribution. This will give a value z=1.88.
Then, we can convert this z-score to our distribution:

Answer:
x =417.6
Step-by-step explanation:
0.5x+78.2=287
Subtract 78.2 from each side
0.5x+78.2-78.2=287-78.2
.5x =208.8
Divide each side by .5
.5x/.5 = 280.8/.5
x =417.6
1. - 3, +4 2. +2, - 5 3. +9, +1
To find the x-intercept, substitute in 0 for y and solve for x. To find the y-intercept, substitute in 0 for x and solve for y.
x-intercept: (9/4,0)
y-intercept: (0,−9)
The answer or value to this question will be D