What is the mass of sodium thiosulphate pentahydrate required to prepare 250cm3 of a 0.14mol/dm3 solution
2 answers:
Answer:
Mass = 8.68g
Explanation:
Mass = Concentration × Molar mass × Volume (in dm^3)
but, concentration = 0.14 mol/dm^3.
volume = 250 cm^3 = 0.25 dm^3.
Molar mass of Na2S2O3 . 5H2O
= (2×23)+(2×32)+(3×16)+(5×18)
= 248 g/mol
hence, mass = 0.14 × 248 × 0.25
Mass = 8.68 g.
I HOPE IT'S OK?
Answer:
Strength of the sodium thiosulphate solution to be produced is 0.150M= 0.150mol/L×248.2g/mol=37.23g/L. So 1L or 1000 mL solution ...
Missing: 0.14mol/dm3 | Must include: 0.14mol/dm3
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