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3 years ago

A.

Mathematics

1 answer:

PtichkaEL [24]3 years ago

4 0

Answer: C an equilateral triangle

Step-by-step explanation:

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Kayce and her friends are renting a summer house together. The eight friends will spend 6 days at this house. The overall cost i

Doss [256]

Answer:

Step-by-step explanation: First you would do this 1260.90 divided by 6 = 210. So then you would multiply 210 x 2 = 420. $420 is how much the people who are staying for 6 days. Then since we know it’s $210 per day, we would subtract $420 from 1260.90 and we would get 840.90. Divide that by 6 and get 140. 140 is how much those two people are paying for 2 nights.

6 0

3 years ago

Which expressions are equivalent to 78 • 7? Select all that apply. HINT: There are 3 correct answers.

Snezhnost [94]

Answer:

None because 78 * 7 = 546

Step-by-step explanation:

8 0

3 years ago

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A trapezoid has a height of 10xy centimeters. It's shorter base is 15y centimeters, and it's longer base is 26y centimeters. Use

Zina [86]

Answer:

1233

Step-by-step explanation:

3 0

3 years ago

Srry again plz help me

JulijaS [17]

Answer:

A) 80 calories

B) 4 grams

C) 0.26666

4 0

3 years ago

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write an equation for an ellipse centered at the origin, which has foci at (+-3,0) and co vertices at (0+-4)

natali 33 [55]

Answer:

The equation for an ellipse centered at the origin with foci at (-3, 0) and (+3, 0) and co-vertices at (0, -4) and (0, +4) is:

$\frac{x^{2}}{7} + \frac{y_{2}}{16} = 1$

Step-by-step explanation:

An ellipse center at origin is modelled after the following expression:

$\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1$

Where:

$a$ , $b$ - Major and minor semi-axes, dimensionless.

The location of the two co-vertices are (0, - 4) and (0, + 4). The distance of the major semi-axis is found by means of the Pythagorean Theorem:

$2\cdot b = \sqrt{(0-0)^{2}+ [4 - (-4)]^{2}}$

$2\cdot b = \pm 8$

$b = \pm 4$

The length of the major semi-axes can be calculated by knowing the distance between center and any focus (c) and the major semi-axis. First, the distance between center and any focus is determined by means of the Pythagorean Theorem:

$2\cdot c = \sqrt{[3 - (-3)]^{2}+ (0-0)^{2}}$