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saul85 [17]
3 years ago
6

Subtract.

Mathematics
1 answer:
Rom4ik [11]3 years ago
7 0
(2x + 2) - (3x + 11)
Remove the parentheses
2x + 2 - 3x + 11
And then combine like terms
So the answer is:
-x - 9
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Y = (x+3)(x+3) <br><br> What does it look like on a graph?
puteri [66]
Mark Brainliest please

I think it looks like the image
8 0
2 years ago
Please help I'm lost.
vova2212 [387]

Part 1: Answer:

(x+1)(x+1)(x-6) = x^3 - 4x^2 - 11x - 6

Step-by-step explanation:

To make r a root, include (x-r) as a factor. (-1+1)(-1+1)(-1-6) is zero even though (-1-6) isn't.

(6+1)(6+1)(6-6) is zero.


Part 2 Answer:

Standard form: y = -x^4 + 12

Degree 4

left end goes down, right end goes down.

Step by step: apply the definitions of standard form, polynomial degree, and "end behavior". In other words, read the textbook.


Part 3: Answer: x = 3, x = 8

Step by step:

x^2-11x = -24

x^2-11x+24 = 0

(x-3)(x-8) = 0

x = 3 or x = 8


Part 4a Answer:

quotient 2x^2 + x - 3

remainder 1


Step by step:

2x^2 + x - 3

___________________

x-4 ) 2x^3 - 7x^2 - 7x + 13

2x^3 - 8x^2

__________

0 + x^2 - 7x + 13

x^2 - 4x

____________

0 - 3x + 13

- 3x + 12

______

1


Part 4b answer:

quotient 2x^2 - 6x + 2

remainder -20


Step by step: you have to know exactly what you are doing. Refer to textbook or Wikipedia.


dividend 2x^3 +14x^2 - 58x

divisor x+10

leading coefficient of divisor must be 1

write coefficients of dividend at top

write coefficients of dividend at left


| 2 14 -58 0

-10 | -20 60 -20

___________

| 2 -6 2 -20

Coefficients of quotient are 2 -6 2

Remainder is -20

quotient = 2x^2 - 6x + 2



7 0
3 years ago
As his empire spread throughout the ancient world, Alexander founded roughly how many cities?
Studentka2010 [4]
About 70 Cities in Total.

For his more noteworthy grandness, Alexander established exactly 70 urban areas in the grounds he vanquished and requested them named after himself. Most celebrated, obviously, is Alexandria in Egypt. In India, when his dearest horse kicked the bucket, he requested a city to be constructed named Bucephala.
6 0
3 years ago
Find the Area Of each circle.
Levart [38]

The area of the circle A and B is 86.54 inches and 124.62 mm

According to the statement

we have given that the radius of the circle A and b and we have to find the area of the given circle.

So, we know that the

The area enclosed by a circle of radius r is πr².

So, For area of the circle

For condition A :

diameter = 10.5 inches

then radius = 5.25

Area = πr²

Area = 3.14*27.56

Area = 86.54 inches

Now, For condition B :

radius = 6.3 mm

Area = πr²

Area = 3.14*39.69

Area = 124.62mm

So, The area of the circle A and B is 86.54 inches and 124.62 mm

Learn more about area of the circle here

brainly.com/question/15673093

#SPJ1

5 0
1 year ago
mn is translated 4 units down and 3 units to the right to form PQ which statement describes the length of PQ
cricket20 [7]
It should be 7 hope this helped
7 0
3 years ago
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