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torisob [31]
3 years ago
9

Helppppme plz apercaite

Mathematics
1 answer:
Eddi Din [679]3 years ago
6 0

Answer:

360 inches in total. And she has 60 pieces

Step-by-step explanation:

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What is cot based on the image
kap26 [50]

the answer is b I'm sure

5 0
3 years ago
Read 2 more answers
How do you simplify this equations?
Akimi4 [234]
The answer is:

Square root of 77
—————————
22

You need to rationalize the denominator meaning that you have to get rid of the square root signs in denominator

To get rationalize the denominator you need to multiply both sides by square root of 11

(Square root of 7)(square root of 11)
——————————————————
2(square root of 11)^2

When squaring a square root it makes the square root “go away”

(Square root of 77)
——————————
2(square root of 11^2 or 122) = 2(11)

So:

The answer is

square root of 77
—————————
22

~~hope this helps~~
8 0
4 years ago
The claim is that the IQ scores of statistics professors are normally​ distributed, with a mean greater than 135. A sample of 23
Shalnov [3]

Answer: 1.8446

Step-by-step explanation:

Given claim : \mu>\mu_0,\text{ where }\mu_0=135

Sample size : n=23

Sample mean : \overline{x}=140

Standard deviation : \sigma = 13

The test statistic for population mean is given by :-

z=\dfrac{x-\mu_0}{\dfrac{\sigma}{\sqrt{n}}}

\Rightarrow\ z=\dfrac{140-135}{\dfrac{13}{\sqrt{23}}}\\\\\Rightarrow\ z=1.84455058589\approx1.8446

Hence, the value of test statistic =  1.8446

5 0
3 years ago
How can the Fundamental Theorem of Algebra be used to show that any polynomial of odd degree has at least one root?
iragen [17]

Answer:

<h2> I want to prove that every real polynomial of odd degree has at least one real root, using the intermediate value theorem.</h2><h2 /><h2>Let </h2>
6 0
3 years ago
Solve for x.<br> 2/3x= - 10
aliya0001 [1]

Step-by-step explanation:

\frac{2}{3} x =  - 10 \\  \frac{2x}{3}  =  - 10 \\ 2x =  - 10 \times 3 \\ 2x =  - 30 \\ x =  \frac{ -30}{2}  \\ x =  - 15

5 0
3 years ago
Read 2 more answers
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