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Serga [27]
3 years ago
12

Please help me on this because I'm not sure if it's a decimal or not

Mathematics
1 answer:
anzhelika [568]3 years ago
3 0
THERE IS NO PICTURE TO ANSWER THIS
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If someone worked 10 :00 to 1:00 how many hours would they have worked
nirvana33 [79]
10 to 11 = 1 hr
11 to 12 = 1 hr
12 to 1 = 1 hr

total  = 3 hours
7 0
3 years ago
Read 2 more answers
Determine if the statement is always, sometimes or never true.
Romashka-Z-Leto [24]

Let

x--------> the measure of the adjacent interior angle

y--------> the measure of an exterior angle at the vertex of a polygon

we know that

The measure of the adjacent interior angle and the measure of an exterior angle at the vertex of a polygon are supplementary angles

so

x+y=180°

<u>Examples</u>

case 1)

<u>In a square</u>

x=90°

so

y=180-90=90°

x=y

In this case

The measure of an exterior angle at the vertex of a polygon equals the measure of the adjacent interior angle

case 2)

<u>an equilateral triangle</u>

x=60°

so

y=180-60=120°

x\neq y

In this case

The measure of an exterior angle at the vertex of a polygon is not equals the measure of the adjacent interior angle

therefore

<u>the answer is</u>

sometimes



4 0
3 years ago
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Solve for n 50 points <br><br> a=p(1+r/n)^rn
Andreyy89

Answer:

n = \frac{r}{\sqrt[nt]{\frac{a}{p}} -1 }

Step-by-step explanation:

a=p(1+\frac{r}{n} )^{nt}

\frac{a}{p} =(1+\frac{r}{n} )^{nt}

\sqrt[nt]{\frac{a}{p}}  =(1+\frac{r}{n} )

\sqrt[nt]{\frac{a}{p}} -1 =(\frac{r}{n} )

n = \frac{r}{\sqrt[nt]{\frac{a}{p}} -1 }

[ Do not confuse, as there are 2 n's, one in subject and another as power. We can never make the power or in a root, the subject. In order to solve for n, we have to make the character "n", the subject. ]

8 0
1 year ago
PLS HELP!!! link attached &lt;333 will mark brainliest.
abruzzese [7]

Answer:

21 t-shirts, 13 sweatshirts is the answer

7 0
3 years ago
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The graph represents the profit earned on the sale of boxes of cookies.
scoundrel [369]

Answer:

The answer Is B

Step-by-step explanation:

I took the test

4 0
2 years ago
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