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chubhunter [2.5K]
3 years ago
15

At Central High School, 28% of the students are Freshmen, 26% are Sophomores, 24% are Juniors, and 22% are Seniors. The student

manager of the school newspaper would like to conduct a survey to estimate the proportion of each class that plans to attend the upcoming Football game. She suggests surveying a random sample of 100 students, but specifically by selecting random samples of 28 Freshmen, 26 Sophomores, 24 Juniors, and 22 Seniors. Which of the following is a true statement about this sampling procedure?
(A) This is a simple random sample because students of every class have an equal chance of being selected.
(B) This is a cluster random sample because there are 4 groups of students that are to be selected.
(C) This is a convenience sample because only 100 students are surveyed, which is a manageable size.
(D) This is a stratified random sample because a separate random sample is selected from each class
(E) Yes, because the difference between the sample proportion and the population proportion is 0.04, which is less than 0.05.
Mathematics
1 answer:
Jet001 [13]3 years ago
4 0

Answer:

(D) This is a stratified random sample because a separate random sample is selected from each class

Step-by-step explanation:

A sample of size n is defined to be a stratified random sample if it is selected from a population which has been divided into a number of non overlapping groups or sub populations called strata, such that part of the sample is drawn at random from each stratum.

It is to be emphasized that good stratification requires that each of these strata should be internally homogeneous but externally should differ from one another.

The advantage of stratified sampling is low cost , greater accuracy and better coverage.

If we analyze the given scenario a sample is selected from each strata depicting its corresponding  percentage in the population.  It is internally homogeneous but externally different.

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A triangle weighs 3 grams and a circle weighs 6 grams. Find the weight of a square in Hanger A and the weight of a pentagon in H
Zanzabum

Answer:

Equation of Hanger A:

x + y = z

z = 9 grams

Equation for hanger B

x + y = p

p = 9 grams

Step-by-step explanation:

Note: This question is not complete, and lacks necessary data to answer this question. But for the sack of concept, we wil be solving this question using our own data.

Data given:

Triangle weight = 3 grams

Circle weight = 6 grams

There are two hangers A and B.

We have to find weight of the square in Hanger A and weight of the pentagon in Hanger B.

So, for your understanding I have drawn the two hangers A and B. In A we have triangle and circle on the LHS and the square on the right. On the other hand, we have pentagon on the right and triangle and circle.

Sketch is attached in the attachment.

Let's suppose: Hanger A is balanced, So,

Triangle weight = 3 grams = x

Circle weight = 6 grams = y

weight of the pentagon in Hanger B = p

weight of the square in Hanger A = z =?

So,

Equation of Hanger A:

x + y = z

z = 3 + 6

z = 9 grams  = weight of the square in Hanger A

Similarly for Hanger B.

Equation for hanger B

x + y = p

p = 3 + 6

p = 9 grams

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