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nadezda [96]
3 years ago
8

Join zoom meet id=547 458 9345pw=sencHURI​

Computers and Technology
2 answers:
Julli [10]3 years ago
7 0

Answer:

you're joking here lol

amm18123 years ago
7 0

Answer:

im not joining

Explanation:

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What are binary code​
s2008m [1.1K]

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Binary code is a coding system using binary digits 0 and 1 to represent a letter, digit, or other characters in a computer or other electronic device. The binary code assigns a pattern of binary digits, also known as bits, to each character, instruction, etc.

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How will advertising and communications change as technology improves?????? HELP PLEASE :0 !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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Technology changes advertising and communications by increasing the outreach of people that will get the message, and increasing the speed at which they get the message. Which in turn makes the advertising more relevent because they can release more product to a wider audience during a specific time period.


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Can someone tell me what this means Higfaa
Arisa [49]

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it's a Jamaican slang

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it depends on the wah it is used

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Why crt and plasma are not used in laptop ?​
AlekseyPX

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Plasma monitors are power hungry devices 2 - 3 times more than a CRT monitor making this technology unfit for use in portable devices like laptop computers where batteries are used as the power source. Plasma monitors are extremely susceptible to screen burn.

Explanation: pls mark my answer as brainlist

6 0
2 years ago
You are given a list of n positive integers a1, a2, . . . an and a positive integer t. Use dynamic programming to design an algo
Anna11 [10]

Answer:

See explaination for the program code

Explanation:

The code below

Pseudo-code:

//each item ai is used at most once

isSubsetSum(A[],n,t)//takes array of items of size n, and sum t

{

boolean subset[n+1][t+1];//creating a boolean mtraix

for i=1 to n+1

subset[i][1] = true; //initially setting all first column values as true

for i = 2 to t+1

subset[1][i] = false; //initialy setting all first row values as false

for i=2 to n

{

for j=2 to t

{

if(j<A[i-1])

subset[i][j] = subset[i-1][j];

if (j >= A[i-1])

subset[i][j] = subset[i-1][j] ||

subset[i - 1][j-set[i-1]];

}

}

//returns true if there is a subset with given sum t

//other wise returns false

return subset[n][t];

}

Recurrence relation:

T(n) =T(n-1)+ t//here t is runtime of inner loop, and innner loop will run n times

T(1)=1

solving recurrence:

T(n)=T(n-1)+t

T(n)=T(n-2)+t+t

T(n)=T(n-2)+2t

T(n)=T(n-3)+3t

,,

,

T(n)=T(n-n-1)+(n-1)t

T(n)=T(1)+(n-1)t

T(n)=1+(n-1)t = O(nt)

//so complexity is :O(nt)//where n is number of element, t is given sum

6 0
3 years ago
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