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never [62]
3 years ago
7

Please help me very important

Computers and Technology
1 answer:
3241004551 [841]3 years ago
4 0

Answer:

C, Or D.

Explanation:

<em>Because A speed enhancing hard drive Can store any type of quick file if you just click on it will load fast. Same thing goes for a hard drive but you have to transfer the file</em>

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The electric company gives a discount on electricity based upon usage. The normal rate is $.60 per Kilowatt Hour (KWH). If the n
katrin2010 [14]

Answer:

The cpp program for the given scenario is shown below.

#include <stdio.h>

#include <iostream>

using namespace std;

int main()

{

   //variables to hold both the given values

   double normal_rate = 0.60;

   double rate_1000 = 0.45;

   //variable to to hold user input

   double kwh;

   //variable to hold computed value

   double bill;

   std::cout << "Enter the number of kilowatt hours used: ";

   cin>>kwh;

   std::cout<<std::endl<<"===== ELECTRIC BILL ====="<< std::endl;

   //bill computed and displayed to the user

   if(kwh<1000)

   {

       bill = kwh*normal_rate;

       std::cout<< "Total kilowatt hours used: "<<kwh<< std::endl;

       std::cout<< "Rate for the given usage: $"<<normal_rate<< std::endl;

       std::cout<< "Total bill: $" <<bill<< std::endl;

   }

   else  

   {

       bill = kwh*rate_1000;

       std::cout<< "Total kilowatt hours used: "<<kwh<< std::endl;

       std::cout<< "Rate for the given usage: $"<<rate_1000<< std::endl;

       std::cout<< "Total bill: $" <<bill<< std::endl;

   }

   std::cout<<std::endl<< "===== BILL FOR GIVEN VALUES ====="<< std::endl;

   //computing bill for given values of kilowatt hours

   double bill_900 = 900*normal_rate;

   std::cout << "Total bill for 900 kilowatt hours: $"<< bill_900<< std::endl;

   double bill_1754 = 1754*rate_1000;

   std::cout << "Total bill for 1754 kilowatt hours: $"<< bill_1754<< std::endl;

   double bill_10000 = 10000*rate_1000;

   std::cout << "Total bill for 10000 kilowatt hours: $"<< bill_10000<< std::endl;

   return 0;

}

OUTPUT

Enter the number of kilowatt hours used: 555

===== ELECTRIC BILL =====

Total kilowatt hours used: 555

Rate for the given usage: $0.6

Total bill: $333

===== BILL FOR GIVEN VALUES =====

Total bill for 900 kilowatt hours: $540

Total bill for 1754 kilowatt hours: $789.3

Total bill for 10000 kilowatt hours: $4500

Explanation:

1. The program takes input from the user for kilowatt hours used.

2. The bill is computed based on the user input.

3. The bill is displayed with three components, kilowatt hours used, rate and the total bill.

4. The bill for the three given values of kilowatt hours is computed and displayed.

3 0
3 years ago
Only class b and class c networks can be subnetted true or false
Alona [7]
Class b and c networks cannot be sub netted.
 false<span />
4 0
3 years ago
HELP ASAP, AND YES I KNOW, WRONG CATEGORY. SORRY!
Anastasy [175]

Answer:

A. ensemble.

Explanation:

A musical ensemble can be defined as a group of people who play instrumental and vocal music. It is also known as a music group and carries a distinct name. The word ensemble is derived from the Middle French ensemblée, meaning together at the same time.

A rock band will come under the category of a musical ensemble as it is also a group of people performing instrumental music or vocal music.

Therefore, option A is correct.

3 0
3 years ago
Which of the following is typically used in a flowchart to indicate a decision?
Vilka [71]
Diamond is typically used in a flowchart or indicate a decision.
6 0
3 years ago
Two files named numbers1.txt and numbers2.txt both have an unknown number of lines, each line consisting of a single positive in
Reika [66]

Answer:

see explaination for program code

Explanation:

scalar_product = 0

li=[]

li2=[]

#reading numbers1.txt and numbers2.txt intoli and li2 respectively

with open('numbers1.txt') as n1, open('numbers2.txt') as n2:

for line1 in n1:

li.append(int(line1))

for line2 in n2:

li2.append(int(line2))

#storing min list size into variable l

a=len(li)

b=len(li2)

if a<b:

l=a

else:

l=b

#calculating scalar product

for i in range(l):

scalar_product=scalar_product+li[i]*li2[i]

print("scalar product is",scalar_product)

6 0
3 years ago
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