Answer:
m
Explanation:
= slit width = 0.1 mm = 0.1 x 10⁻³ m
= wavelength of monochromatic light = 500 nm = 500 x 10⁻⁹ m
= Distance of the screen = 10 m
= Spacing between successive minima
Spacing between successive minima is given as
![w = \frac{2D\lambda }{d}](https://tex.z-dn.net/?f=w%20%3D%20%5Cfrac%7B2D%5Clambda%20%7D%7Bd%7D)
Inserting the values given
![w = \frac{2(10)(500\times10^{-9}) }{0.1\times10^{-3}}](https://tex.z-dn.net/?f=w%20%3D%20%5Cfrac%7B2%2810%29%28500%5Ctimes10%5E%7B-9%7D%29%20%7D%7B0.1%5Ctimes10%5E%7B-3%7D%7D)
m
Answer:
The combined velocity of the girl and the platform after the jump is 1.14 m/s.
Explanation:
From the law of conservation of momentum:
m1u1 = (m1 + m2)v
m1 is mass of the girl = 39 kg
m2 is mass of the hanging platform = 125 kg
u1 is initial speed of the girl = 4.8 m/s
v is combined velocity of the girl and the platform after the jump
v = m1u1/(m1+m2) = 39×4.8/(39+125) = 187.2/164 = 1.14 m/s
Answer:
356K
Explanation:
use this formula for brayton cycle
∩=1-(Tin/Tout)
where
∩=efficiency
Tin= inlet temperature
Tout=
outlet temperature
solving
Tout=Tin/(1-∩)
Tout=267K/(1-0.25)
Tout=356K
<span>here's a cheap trick
it would take the same time to accelerate from rest to top speed
as it would take to decelerate from top speed to zero
so
instead of
d = Vi t + 1/2 a t^2 where Vi is positive and a is negative
we'll use
Vi = 0 and a is positive
giving
85 = 0 + 1/2 (0.43) t^2 = 0.215 t^2
t^2 = 395.345
t = 19.88s or 20. s to 2 sig figs
or we ccould find Vi from
Vf*2 = Vi^2 + 2 a d
0 = Vi^2 + 2 (0.43) 85
Vi^2 = 71.4
Vi = 8.45m/s
then
85 = 8.45 t + 1/2 (-0.43) t^2
85 = 8.45 t - 0.215 t^2
0.215 t^2 - 8.45 + 85 = 0
t = 19.65s or 20. s to 2 s.f.(minor difference arises from rounding Vi)
or another cheap trick
when a is constant
Vavg = (Vf + Vi) /2 = 8.45/2 = 4.225
and
d = Vavg t
85 = 4.225 t
t = 20.12 or 20. s to 2 s.f. (minor differences from intermidiate roundings)
anyway you choose you get 20. s</span>
Answer:
rad/s
Explanation:
The wave function is:
where :
k = wave number
x = position of a point on the wave
= angular frequency
t = time
What is another way to express the angular frequency (omega)
Angular frequency (omega) can be express as :
rad/s ( i.e one repetition that it takes to repeats itself)