In physical chemistry, the mean free path is the average distance between the atoms during collision. Its formula is
where d is the diameter of the Nitrogen atom (d = 310 x 10^-7 m), Na is Avogadro's number (Na=6.022 x 10^23), R is the gas constant (8.314 J/mol-K), T is the absolute temperature (T= 20 + 273 = 293 K). Substituting the values,
P = 6.32 x 10^-13 Pascals
Answer:
3091.56
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.81 m/s² (positive downward and negative upward)
Distance traveled in the first stage is 1093.75 m
Velocity at the end of first stage is 87.5 m/s
Acceleration of the second stage is 4.5 m/s²
Distance traveled in the second stage is 1100 m
Distance traveled after the second stage has stopped firing is 894.81 m
Total height the rocket reached = 1093.75+1100+897.81 = 3091.56 m
Answer:
The velocity of the center of mass of the two-object system remains constant during the experiment.
<span>Any substance that yields a hydrogen ion when placed in a water solution is called an acid.</span>
Answer:
Part A:
Part B:
Explanation:
Part A:
To calculate the number of free electrons n we use the following formula::
n=1.5N-Au
Where N-Au is number of gold atoms per cubic meter
So:
Part B:
n is calculated above which is 8.85*10^{28}m^{-3}
Charge on electron=1.602*10^{-19}
Elec- Conductivity= 4.3*10^{7}
