Question

An ideal heat engine absorbs heat at 100°C and exhausts heat at 0°C. What is its percent efficiency?

Answer 1

Answer:

26.8 %

Explanation:

TH = 100°C = 100 + 273 = 373 K

Tc = 0°C = 273 K

The efficiency of the heat engine is given by

$\eta = 1-\frac{T_{c}}{T_{H}}$

$\eta = 1-\frac{273}{373}$

η = 0.268

η = 26.8 %

Thus, the efficiency of the heat engine is 26.8 %.