All categories

3 years ago

What is the scale factor of this dilation?

Mathematics

2 answers:

maw [93]3 years ago

6 0

Answer: 2 over 1

Step-by-step explanation: Division and cause i am in Honors Geometry high school

DedPeter [7]3 years ago

4 0

Answer: The scale factor of dilation is 2:1

Step-by-step explanation: You can see that the sides of the blue triangle are of lenght 4 and 3, and for the red triangle, the lenghts are 8 and 6 (so the lenghts are doubled)

Here we can see that the dilation has a factor of dilation = 2 (meaning that the red triangle sides have two times the lenghts of the blue triangle sides). The factor can be written as 2:1

You might be interested in

An electronics store stocks a computer with a price of $800. during a promotion, the manager of the store offers a 30% discount

OLEGan [10]

Answer:

$560

Step-by-step explanation:

800/10 = 80

80 x 7 = 560

3 0

3 years ago

Read 2 more answers

Solve a=9y+3xy for y

Sauron [17]

Answer:

y=a/(9+3x)

Step-by-step explanation:

Reverse: 9y+3xy=a

y(9+3x)=a

y=a/(9+3x)

4 0

3 years ago

Pls help i dont understand :( will mark brainliest!!

kolezko [41]

Answer:

375< y < 525

Step-by-step explanation:

The minimum is 15* 25 = 375

the maximum is 15 * 35 =525

He can earn any amount between these two values

7 0

3 years ago

Please could you find the answers to the questions in the attachment.

Fudgin [204]

( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ )we need 3 equations
1. midpoint equation which is ( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ ) when you have 2 points

2. distance formula which is D= $\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height

so

x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=( $\frac{11+19}{2} , \frac{10+6}{2}$ )
midpoint=( $\frac{30}{2} , \frac{16}{2}$ )
midpoint= (15,8)

point x=(15,8)

y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=( $\frac{5+21}{2} , \frac{8+0}{2}$ )
midpoint=( $\frac{26}{2} , \frac{8}{2}$ )
midpoint=(13,4)

Y=(13,4)

legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D= $\sqrt{(19-11)^{2}+(6-10)^{2}}$
D= $\sqrt{(8)^{2}+(-4)^{2}}$
D= $\sqrt{64+16}$
D= $\sqrt{80}$
D= $4 \sqrt{5}$
BC= $4 \sqrt{5}$

X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D= $\sqrt{(13-15)^{2}+(4-8)^{2}}$
D= $\sqrt{(-2)^{2}+(-4)^{2}}$
D= $\sqrt{4+16}$
D= $\sqrt{20}$
D= $2 \sqrt{5}$
XY= $2 \sqrt{5}$

the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC= $4 \sqrt{5}$ and XY= $2 \sqrt{5}$

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D= $\sqrt{(21-5)^{2}+(0-8)^{2}}$
D= $\sqrt{(16)^{2}+(-8)^{2}}$
D= $\sqrt{256+64}$
D= $\sqrt{320}$
D= $4 \sqrt{2}$
AD= $4 \sqrt{2}$

so we have
AD= $4 \sqrt{2}$
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
( $4 \sqrt{2}+4 \sqrt{5}$ ) times 1/2 times $2 \sqrt{5}$ =
( $4 \sqrt{2}+4 \sqrt{5}$ ) times \sqrt{5} [/tex] =
$4 \sqrt{10}+4*5$ = $4 \sqrt{10}+20$ =80 $\sqrt{10}$ =252.982

X=(15,8)
Y=(13,4)
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$
Area=80 $\sqrt{10}$ square unit or 252.982 square units

7 0

3 years ago

Clare has $54 in her bank account. A store credits her account with a $10 refund. How much does she now have in the bank?

lorasvet [3.4K]

She will now have 64 dollars in her bank account

6 0

3 years ago