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ArbitrLikvidat [17]
3 years ago
15

Need help w the circled ones plsssss

Mathematics
2 answers:
Wewaii [24]3 years ago
4 0

Answer: #1. yes it's a function #6. the graph is increasing at (-oo , 2) , #7.  the graph is decreasing at (2,oo) ,

Step-by-step explanation:

hope it helps

Nutka1998 [239]3 years ago
3 0

6. It is increasing from (-infinity, 4) or ]  i am not sure

7. It is decreasing from ( or [4, infinity)

If the arrow kept on going the f(-12) = x for example, f(4)=2

Important things to know f(x)=y and (x,y)

I am sorry that I can not help with the others!!!

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The length of a rctangle is to more than the
hram777 [196]

Answer:

  19 m

Step-by-step explanation:

The width is 2 less than the length, so the perimeter is ...

  P = 2(L +W)

  72 = 2(L +(L -2))

  76 = 4L . . . . . . . . add 4

  19 = L

The length of the rectangle is 19 meters.

7 0
3 years ago
PLEASE HELP ME!!!!!!!!!!!!!<br> Let f(x)=x^2+7 and g(x)=x-3/x find (f o g) (-8)
sashaice [31]
X=-56 that is the answer
3 0
3 years ago
Read 2 more answers
Over the last three evenings, Yoko received a total of 73 phone calls at the call center. The third evening, she received 3 time
stealth61 [152]
The first evening she received x calls.
The second evening she received 7 fewer calls than the first evening, so she received x-7 calls.
The third evening she received 3 times as many calls as the first evening, so she received 3x calls.
Over the three evenings she received 73 calls altogether.

x+x-7+3x=73 \\&#10;5x-7=73 \\&#10;5x=73+7 \\&#10;5x=80 \\&#10;x=\frac{80}{5} \\&#10;x=16 \Leftarrow \hbox{the first evening} \\ \\ \hbox{the second evening:} \\&#10;x-7=16-7=9 \\ \\ \hbox{the third evening:} \\&#10;3x=3 \times 16=48

The first evening she received 16 calls, the second evening she received 9 calls, the third evening she received 48 calls.
3 0
3 years ago
Use a related equation that has the variable on one side. then simplify the other side. j – 5 = 61
AlladinOne [14]
<span>adding 5 on both sides we get j=61+5 simplifying to j=66</span>
5 0
3 years ago
Two teams are distributing information booklets. Team A distributes 60% more boxes of booklets than Team B, but each box of Team
Marina CMI [18]

Answer:

The answer is option C.  

Step-by-step explanation:

Team A distributes 60% more boxes of booklets than Team B.

But each box of Team A’s has 60% fewer booklets than each box of Team B’s.

We can define the ratio as:

Team A boxes : team B boxes = 160:100 = 8:5

We can say that team A distributes 8x boxes while team B distributes 5x boxes.

Given that team A has 60% fewer means 40% booklets in each box. So,

Team A booklets per box : Team B booklets per box = 40:100 = 2:5

Therefore, team A's boxes have 2y booklets each while team B's have 5y booklets each.

Then the total number of booklets = 16xy+ 25xy =41xy

Now, books count can be integers which means x and y must be integers and divisible by 41.

Out of all the options, 4100 is divisible by 41.

Therefore, the answer is option C.  

7 0
2 years ago
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