The force F newtons between two magnetic poles is given by the formula
F = \displaystyle\frac{1}{500r^{2}} where r m is their distance apart.
Find the rate of change of the force when the poles are 0.2 m apart and the distance between them is increasing at a rate of 0.03 ms^-1"
\displaystyle\frac{dF}{dt} = \frac{dr}{dt}*\frac{dF}{dr}
dr/dt = 0.03 ms^-1 and df/dr = -1000r^-3.....where r = 0.2m so don't i just do for df/dr, -1000*(0.2^-3) and then multiply it by 0.03???
Answer:
I believe Henrey is wrong
Step-by-step explanation:
because the roots of the quadratic function are
<em>"</em><em>(</em><em>x</em><em>=</em><em> </em><em>3</em><em>/</em><em>4</em><em>,</em><em> </em><em>-</em><em>2</em><em>)</em><em>.</em><em>"</em>
Once you complete the square, the simplified version of this equation is
(2x - 1)^2= 0
If you want to solve for x, subtract 1 and divide by 2.
x = 0.5
