9 servings, 5×3=15 but for each 5 equals 3 so,3 +3+3 =9 because 5 is a serving
Answer:
1.We say a coin is fair if it has probability 1/2 of landing heads up and probability 1/2 of landing tails up. What is the probability that if we flip two fair coins, both will land heads up? It seems plausible that each should be equally likely. If so, each has probability of 1/4.
2.The probability of getting heads on the toss of a coin is 0.5. If we consider all possible outcomes of the toss of two coins as shown, there is only one outcome of the four in which both coins have come up heads, so the probability of getting heads on both coins is 0.25.
3.his states that the probability of the occurrence of two mutually exclusive events is the sum of their individual probabilities. As you can see from the picture, the probability of getting one head and one tail on the toss of two coins is 0
Step-by-step explanation:
Divide each term by πr2 π r 2 and simplify. Divide each term in πr2h=V π r 2 h = V by πr2 π r 2 .
Answer:
Step-by-step explanation:
He will earn 368 if he sold 6 bars
Answer:
T=3
Step-by-step explanation:
4-T = 3(t-1) -5
4-t=3T -3-5
^^ distribute
-T=3T-12
^^combine like terms and subtraction prop. of equality.
-4T=-12
^^ subtraction property of equality
(-4T=12)/-4
^^ thats just getting rid of the -sign, then its also simpliying
T=3
