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cluponka [151]
3 years ago
7

How do i find the slope of 5x-12y=24??

Mathematics
1 answer:
Aloiza [94]3 years ago
7 0
Rearrange into the form y = mx + c

m will be the gradient

5x - 12y = 24

-12y = 24 - 5x

y = (24/-12) - (5/-12)x

y = -2 + (5/12) x

m=5/12

so the gradient is 5/12

Please feel free to ask if you have any questions
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How To Round 17 5/8 To The Nearest Whole Number
Verdich [7]
<span><u><em>Answer:</em></u>
18

<u><em>Explanation:</em></u>
To round a number to the nearest whole number, we would check the fraction part:
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If the fraction is <u>equal to or more than </u>0.5, then we would add 1 to the whole number and eliminate the fraction.

<u>In the given , we have:</u>
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5 0
3 years ago
Consider the following division of polynomials.
Bond [772]

x^4=x^2\cdot x^2. Multiplying the denominator by x^2 gives

x^2(x^2+2x+8)=x^4+2x^3+8x^2

Subtracting this from the numerator gives a remainder of

(x^4+x^3+7x^2-6x+8)-(x^4+2x^3+8x^2)=-x^3-x^2-6x+8

-x^3=-x\cdot x^2. Multiplying the denominator by -x gives

-x(x^2+2x+8)=-x^3-2x^2-8x

and subtracting this from the previous remainder gives a new remainder of

(-x^3-x^2-6x+8)-(-x^3-2x^2-8x)=x^2+2x+8

This last remainder is exactly the same as the denominator, so x^2+2x+8 divides through it exactly and leaves us with 1.

What we showed here is that

\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}

=x^2-x+\dfrac{x^2+2x+8}{x^2+2x+8}

=x^2-x+1

and this last expression is the quotient.

To verify this solution, we can simply multiply this by the original denominator:

(x^2+2x+8)(x^2-x+1)=x^2(x^2-x+1)+2x(x^2-x+1)+8(x^2-x+1)

=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)

=x^4+x^3+7x^2-6x+8

which matches the original numerator.

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3 years ago
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