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3 years ago

5 ( 3 squared x) + 9 ( 3 squared x)

Mathematics

1 answer:

yulyashka [42]3 years ago

5 0

Answer:

42x^2

Step-by-step explanation:

$5(3x^{2} )+9(3x^2)\\\\=(5+9)(3x^2)\\\\=14(3x^2)\\\\=42x^2$

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Find the area of the region between two concentric circular paths. If the radii of the circular paths are 210 m. and 490 m. resp

taurus [48]

Given :

The radii of the circular paths are 210 m. and 490 m.

To Find :

The area of the region between two concentric circular paths.

Solution :

Area of the outer circle :

$\: \qquad \dashrightarrow \sf{{ \pi \: \times {(490)}^{2} {m}^{2}}}$

$\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{7} \times \:490 \times 490 \: {m}^{2}}}$

$\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{ \cancel{7}} \times \cancel{490} \times 490 \: {m}^{2}}}$

$\: \qquad \dashrightarrow \sf{{ \ {22} \times 70 \times 490 \: {m}^{2}}}$

$\: \qquad \dashrightarrow \bf{{ \ 754600 \: {m}^{2}}}$

⠀

Area of the inner circle :

$\: \qquad \dashrightarrow \sf{{ \pi \: \times {(210)}^{2} {m}^{2}}}$

$\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{7} \times \:210 \times 210 \: {m}^{2}}}$

$\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{ \cancel{7}} \times \cancel{210} \times 210 \: {m}^{2}}}$

$\: \qquad \dashrightarrow \sf{{ \ {22} \times 30 \times 210 \: {m}^{2}}}$

$\: \qquad \dashrightarrow \bf{{ \ 138600 \: {m}^{2}}}$

⠀

Therefore,

Area of the region inside the circular paths :

$\: \qquad \dashrightarrow \sf{{ \ (754600 - 138600 ) \: {m}^{2}}}$

$\: \qquad \dashrightarrow \bf{{ \ 616000 \: {m}^{2}}}$

6 0

2 years ago

Write an equation of a line that is perpendicular to 4x +2y = 8

Mashcka [7]

Answer:

Step-by-step explanation:

2y = -4x + 8

y = -2x + 4

perp. 1/2

y - 2 = 1/2(x - 6)

y - 2 = 1/2x - 3

y = 1/2x - 1

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3 years ago

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Nadusha1986 [10]

the answer I knew but I forgot at ate

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2 years ago

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AlexFokin [52]

Answer:

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2 years ago

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JulijaS [17]

Answer:

32%

Step-by-step explanation:

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