What is the relationship between RR' and SS'?
Point-slope form of a line: we need a point (x₀,y₀) and the slope "m".
y-y₀=m(x-x₀)
slope intercept form :
y=m+b
m=slope
If the line is parallel to y=2/3 x-0, the line will have the same slope, therefore the slope will be: 2/3.
Data:
(8,4)
m=2/3
y-y₀=m(x-x₀)
y-4=2/3(x-8)
y-4=2/3 x-16/3
y=2/3 x-16/3+4
y=2/3 x-4/3 (slope intercept form)
Answer: The equation of the line would be: y=2/3 x-4/3.
if we have the next slope "m",then the perendicular slope will be:
m´=-1/m
We have this equation: y=2/3 x+0; the slope is: m=2/3.
The perpendicular slope will be: m`=-1/(2/3)=-3/2
And the equation of the perpendicular line to : y=2/3 x+0, given the point (8,4) will be:
y-y₀=m(x-x₀)
y-4=-3/2 (x-8)
y-4=-3/2 x+12
y=-3/2x + 12+4
y=-3/2x+16
answer: the perpendicular line to y=2/3 x+0 , given the point (8,4) will be:
y=-3/2 x+16
Answer:
I cant see the question its very blurry
Step-by-step explanation:
The distributive property: a(b + c) = ab + ac
(x - 3)(4x + 2) = (x)(4x + 2) + (-3)(4x + 2)
= (x)(4x) + (x)(2) + (-3)(4x) + (-3)(2) = 4x² + 2x - 12x - 6
<h3>= 4x² - 10x - 6</h3>
A) (-2)² ≠ -4 is your answer
Explanation:
(-2)² = (-2)(-2)
(-2) x (-2) = 4
∴ A) (-2)² ≠ -4
hope this helps
