Answer:
YES MA'AM
Step-by-step explanation:
Answer:
x = 0 and x = 6
Step-by-step explanation:
See the graph attached to this question.
It is clear from the graph that the curve touches x-axis i.e. y becomes zero at points x = 0 and x = 6
Therefore, the give parabola has zeros at x = 0 and x = 6. (Answer)
Zeros of a function y = f(x) are determined from the equation f(x) = 0 and solving it we will get the x-values which are the zeros of the function.
bearing in mind that standard form for a linear equation means
• all coefficients must be integers, no fractions
• only the constant on the right-hand-side
• all variables on the left-hand-side, sorted
• "x" must not have a negative coefficient
![\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-7=1[x-(-1)]\implies y-7=x+1 \\\\\\ y=x+8\implies \boxed{-x+y=8}\implies \stackrel{\textit{standard form}}{x-y=-8}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Bpoint-slope%20form%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y-y_1%3Dm%28x-x_1%29%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D%5Cimplies%20y-7%3D1%5Bx-%28-1%29%5D%5Cimplies%20y-7%3Dx%2B1%20%5C%5C%5C%5C%5C%5C%20y%3Dx%2B8%5Cimplies%20%5Cboxed%7B-x%2By%3D8%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bstandard%20form%7D%7D%7Bx-y%3D-8%7D)
just to point something out, is none of the options, however -x + y = 8, is one, though improper.
Answer:
2/5
Step-by-step explanation:
Answer:
B) 5 + 17i is your answer.
Step-by-step explanation:
In order to write this equation as a complex number in standard form, you must first simplify each term.
<em>Apple the distributive property.</em>
21 - 4i - 1 * 16 - (7i) + 28i
<em>Multiply -1 by 16.</em>
21 - 4i -16 - (7i) + 28i
<em>Multiply 7 by -1.</em>
21 - 4i - 16 - 7i + 28i
<em>Now simplify by adding terms :)</em>
<em>Subtract 16 from 21.</em>
5 - 4i - 7i + 28i
<em>Subtract 7i from -4i.</em>
5 - 11i + 28i
<em>Add -11i and 28i.</em>
= 5 + 17i
