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scoundrel [369]
2 years ago
8

Please help EDGINUITY 2022

Mathematics
1 answer:
enot [183]2 years ago
4 0
D. 3090

Explanation:
6(103)= 618
618(5)= 3090
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9.07 x 12 and 12.015 x 0.14
blagie [28]

Answer:

183.079764 if you round it would be around 183

Step-by-step explanation:

Have amazing day!

4 0
3 years ago
Which sampling method is MOST appropriate in estimating the average number of votes for each candidate in an election across a c
kaheart [24]

Answer:

B. Stratified sampling, because there are specific subgroups to investigate.

Step-by-step explanation:

Stratified Sampling is a sampling method and is used when the population has subgroups with different characteristics. Random sampling is applied in each of the sub-groups <em>proportional </em>to their size and then these samples <em>combined </em>together to create sample of the study.

Since there are three towns with people from different occupations ( retirees,business owners, office workers), it is better to use stratified sampling method.

4 0
3 years ago
Can you solve this problem please im having trouble with this question ​
Degger [83]

Answer:

The answer is 3.7

Step-by-step explanation:

Use cross multiplication to set up the equation then simplify,

17y = 63

  y = 63/17

  y = 3.705

Round to the nearest tenth.

Solution is y = 3.07

Good luck!

3 0
3 years ago
Read 2 more answers
Simplify using order of operations 9 divided by 3 + 4 times 3 divided by 6
Alchen [17]

Answer:

5

Step-by-step explanation:

1. \: 3 + 4 \times 3 \div 6 \\ 2. \: 3 + 12 \div 6 \\ 3. \: 3 + 2 \\ 4. \: 5

7 0
3 years ago
A survey of 80 randomly selected companies asked them to report the annual income of their presidents. Assuming that incomes are
Artyom0805 [142]

Answer:

The 90% confidence interval estimate of the mean annual income of all company presidents is ($579,545, $590,580).

Step-by-step explanation:

The information provided is:

n=80\\\sigma=30,000\\\bar x=585062.50\\\text{Confidence level} = 90\%

The critical value of <em>z</em> for 90% confidence level is, 1.645.

Compute the 90% confidence interval estimate of the mean annual income of all company presidents as follows:

CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\\\\=585062.50\pm 1.645\times\frac{30000}{\sqrt{80}}\\\\=585062.50\pm5517.50\\\\=(579545, 590580)

Thus, the 90% confidence interval estimate of the mean annual income of all company presidents is ($579,545, $590,580).

This interval implies that there is 90% probability that the true mean annual income of all company presidents is within this interval.

4 0
2 years ago
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