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vagabundo [1.1K]
3 years ago
11

Please answer!! 20 points ASAP

Mathematics
1 answer:
lidiya [134]3 years ago
7 0

<u>Answer:</u>

The length of VI to the nearest tenth is 4 cm

Solution:

The plot is like a quadrilateral and the fences are built on the diagonal

We know that for quadrilateral both the diagonals are in same height,  

So as per the picture, \mathrm{GH}=\mathrm{Fl}

Now we know that \mathrm{GV}=6.55 cm; \mathrm{FV}=5.84 cm; \mathrm{VH}=3.27 cm

Hence,

GH = FI

\Rightarrow GV + VH = VI + VF

\Rightarrow 6.55 + 3.27 = VI + 5.84

\Rightarrow VI = 6.55 + 3.27 - 5.84

\Rightarrow VI = 3.98

<u>Rounding off:</u>

  • If the number that we are rounding is followed by 5 to 9, then the number has to be increased to the next successive number.
  • If the number that we are rounding is followed by 1 to 4, then the number has to remain the same.

Here the number to be round off is 3.98, 9 belongs to the first category stated above. So, 3 is increased to 4.

Hence, the length of VI = 4 cm.

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The length of a rectangle is 5959 inches greatergreater than twice the width. if the diagonal is 2 inches more than the​ length,
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Length: 2w + 59

width: w

diagonal: (2w + 59) + 2  = 2w + 61

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(4w² + 118w + 3481) + w²  = 4w² + 122w + 3721

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since width cannot be negative, disregard  1 - 2√61

w = 1 + 2√61  ≈ 16.62

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see explanation

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