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MA_775_DIABLO [31]
3 years ago
14

N+3/4=1/4 solve for n

Mathematics
1 answer:
Hitman42 [59]3 years ago
6 0

Answer:

N = -1/2

Step-by-step explanation:

We are adding in this, so we need to do the opposite to both sides, to get N by itself.

N + 3/4 - 3/4 = 1/4 - 3/4

N = -2/4 or, simplified, -1/2

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There’s a picture of my question plz help :)
Degger [83]

Answer:

1,534 inches squared

Step-by-step explanation:

To find surface area we just solve for the area of all the sides and add those together. A rectangular prism (a box like above) has 6 sides. There are...

2 sides each of the following dimensions:

2(13×26)=

2(338)=676

2(13×11)=

2(143)=286

2(26×11)=

2(286)=572

Add the area of all 6 sides...

676+286+572=1,534

Remember it is squared not cubed.

5 0
3 years ago
A company increased their profits by 145% from last year. If their profits were $127,000 last year, how much did they make this
weqwewe [10]
I got $184,150
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5 0
4 years ago
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Prove (1+sin/csc-cot)-(1-sin/csc+cot)=2(1+cot)​
Aloiza [94]

\dfrac{1+sin}{csc-cot}-\dfrac{1-sin}{csc+cot}=2(1+cot)\\\\\\\text{Proof from LHS }\rightarrow \text{ RHS}\\\\\dfrac{1+sin}{csc-cot}\bigg(\dfrac{csc+cot}{csc+cot}\bigg)-\dfrac{1-sin}{csc+cot}\bigg(\dfrac{csc-cot}{csc-cot}\bigg)\\\\\\\dfrac{csc+cot+sin csc+sincot}{csc^2-cot^2}+\dfrac{-csc+cot+sincsc-sincot}{csc^2-cot^2}\\\\\\\dfrac{2cot+2sincsc}{csc^2-cot^2}\\\\\\\dfrac{2(cot+sincsc)}{1}\\\\\\2\bigg(\dfrac{cos}{sin}+\dfrac{sin\cdot1}{sin}\bigg)\\\\\\2(cot+1)\\\\\\2(1+cot)=2(1+cot)

LHS = RHS \checkmark

3 0
3 years ago
What is 60 to the third power of 10? Plz help me quick!!!!!!! Thx a bunch!
Sphinxa [80]
It would be 1800 bc if you do 60x3=180 180x10=1,800
8 0
3 years ago
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By the square property, if b is a real number , and a2=b, then a=
Serggg [28]

Answer:

a=\sqrt{6},\:a=-\sqrt{6}

Step-by-step explanation:

Given

  • b is a real number
  • a^2=b

as

\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

so

a^2=6

a=\sqrt{b},\:a=-\sqrt{b}

Therefore,

a=\sqrt{6},\:a=-\sqrt{6}

5 0
3 years ago
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