I believe it would be Heat Radiation
Answer: b
Explanation: you have to use both math and science in engineering
Only one strand will be transcribed and the other servers as a coding stand. ... Without it, the single strand DNA with exposed nitrogenous bases is very unstable so two strands actually stabilise the structure.
Answer:
The probability that the child will have type blood B equals <u>3/16</u>.
Explanation:
<u>Available data:</u>
- Individuals with the rare Bombay blood phenotype lack both the A and B antigens in individuals and/or are of hh genotype.
- Cross between two parents that are both of I A I B Hh genotype
Cross: IAIB Hh x IAIB Hh
Gametes) IAH, IAh, IBH, IBh
IAH, IAh, IBH, IBh
Punnett square) IAH IAh IBH IBh
IAH IAIAHH IAIAHh IAIBHH IAIBHh
IAh IAIAHh IAIAhh IAIBHh IAIBhh
IBH IAIBHH IAIBHh IBIBHH IBIBHh
IBh IAIBHh IAIBhh IBIBHh IBIBhh
F1) Genotype
- 1/16 IAIA HH
- 2/16 IAIAHh
- 1/16 IAIAhh
- 2/16 IAIBHH
- 4/16 IAIBHh
- 2/16 IAIBhh
- 1/16 IBIBHH
- 2/16 IBIBHh
- 1/16 IBIBhh
Phenotype
- 3/16 Blood type A
- 6/16 Blood type AB
- 3/16 Blood type B
- 3/16 Blood type 0