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3241004551 [841]
3 years ago
15

Which terms could be used as the first term of the expression below to create a polynomial written in standard form? Check all t

hat apply.
+ 8r2s4 – 3r3s3


s5
3r4s5
–r4s6
–6rs5
Mathematics
2 answers:
mestny [16]3 years ago
5 0

Answer:

3r4s5 would be the best

Ugo [173]3 years ago
4 0

Answer:

3r^{4}s^{5}\\-r^{4}s^{6}

Step-by-step explanation:

<em>The standard form of a polynomial is when its term of highest degree is at first place.</em>

In this case, we have two variables. The grade of each term is formed by the sum of its exponents. That means both given terms have a degree of six. So, the right answers must have a higher degree.

Therefore, the right answers are the second and third choice, because their degrees are 9 and 10 respectively.

You might be interested in
Plz, help me answer this.
Finger [1]

Answer:

B. 5

Step-by-step explanation:

-15 / -3

Both are negative so they cancel each other out.

15 / 3 equals 5

7 0
3 years ago
Read 2 more answers
Find the polynomial equation of least degree with roots -1, 3, and (+/-)3i
jasenka [17]
Each of these roots can be expressed as a binomial:

(x+1)=0, which solves to -1
(x-3)=0, which solves to 3
(x-3i)=0 which solves to 3i
(x+3i)=0, which solves to -3i
There are four roots, so our final equation will have x^4 as the least degree

Multiply them together. I'll multiply the i binomials first:
(x-3i)(x+3i) = x²+3ix-3ix-9i²
x²-9i²
x²+9  [since i²=-1]

Now I'll multiply the first two binomials together:
(x+1)(x-3) = x²-3x+x-3
x²-2x-3
Lastly, we'll multiply the two derived terms together:

(x²+9)(x²-2x-3)   [from the binomial, I'll distribute the first term, then the second term, and I'll stack them so we can simply add like terms together]

x^4 -2x³-3x²
 <u>           +9x²-18x-27</u>
x^4-2x³+6x²-18x-27

7 0
3 years ago
What are the exact solutions of x2 - 3x - 5 = 0? x = the quantity of negative 3 plus or minus the square root of 29 all over 2 x
Vinil7 [7]
x^{2}-3x-5=0 \\  \\ \Delta=(-3)^{2}-4*1*(-5)=9+20=29 \\  \\  \sqrt{\Delta} = \sqrt{29}  \\  \\ x_{1}= \frac{3- \sqrt{29} }{2}  \\  \\ x_{2}= \frac{3+ \sqrt{29} }{2}

<em>\\\ Ben</em>
3 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%7C%20%7Bx%7D%5E%7B2%7D%20%2B%203x%20%2B2%20%7C%20%3C%202x%20%2B%204" id="TexFormula1" titl
Snezhnost [94]

\\ \tt\hookrightarrow |x^2+3x+2|

Either

\\ \tt\hookrightarrow x^2+3x+2

\\ \tt\hookrightarrow x^2+3x+2x

\\ \tt\hookrightarrow x^2+5x+6

\\ \tt\hookrightarrow (x+2)(x+3)

\\ \tt\hookrightarrow x

Or

\\ \tt\hookrightarrow x^2+3x+2

\\ \tt\hookrightarrow x^2+x-2

\\ \tt\hookrightarrow x^2+2x-x-2

\\ \tt\hookrightarrow (x+2)(x-1)

\\ \tt\hookrightarrow x

So

\\ \tt\hookrightarrow x\in (-3,1)

7 0
2 years ago
A game system allows players to design a personal picture. Each picture is designed by choosing from male or female, 8 face shap
astra-53 [7]

Answer:

The number of possible pictures:

N = 2 x 8 x 48 x 12 x 24 x 82 = 18137088

Hope this helps!

:)

6 0
3 years ago
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