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3 years ago

What transformation occurs to the graph f (x) =2x + 3 if the 3 in the equation is changed to a 5?

Mathematics

1 answer:

kodGreya [7K]3 years ago

5 0

The equation will shift up two points

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3 x. 3x²+x-3=0 Find the zeros

Tanya [424]

Answer:

The zeroes of this polynomial are $x_{1} \approx 0.847$ and $x_{2} \approx -1.180$ .

Step-by-step explanation:

Let $3\cdot x^{2}+x - 3 = 0$ , the quickest and most efficient approach to find the zeroes of this second order polynomial is by Quadratic Formula. For all $a\cdot x^{2}+b\cdot x + c = 0$ , roots are determined by:

$x_{1,2} = \frac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}$ (1)

Where $a$ , $b$ , $c$ are coefficients of the polynomial.

If we know that $a = 3$ , $b = 1$ and $c = -3$ , then roots of the polynomial are, respectively:

$x_{1,2} = \frac{-1\pm\sqrt{1^{2}-4\cdot (3)\cdot (-3)}}{2\cdot (3)}$

$x_{1,2} =\frac{-1\pm \sqrt{37}}{6}$

The zeroes of this polynomial are $x_{1} \approx 0.847$ and $x_{2} \approx -1.180$ .

3 0

3 years ago

Express the first quantity as a percentage of the second : 4 m , 10 m

Lena [83]

40% is the answer for the quantity of percentage

6 0

3 years ago

Read 2 more answers

Based on probability and if it is appropriate for a decision to be left up to chance, choose every situation that is both statis

svet-max [94.6K]

The situations that are both statistically fair and morally fair are Situation 2, Situation 3 and Situation 5

<h3>How to categorize the situations?</h3>

For a situation to be fair, the probability of every outcome must be equal.

We can now analyze each option using the above highlight

Situation 1

Alphabets = 26
Probability of vowel = 5/26
Probability of consonant = 21/26

The probabilities of vowels and consonant are not equal.

Hence, this situation is not fair

Situation 2

People = 4

P(Each) = 1/4

The probability of each participant is equal in the above scenario i.e. 1/4

Hence, this situation is fair

Situation 3

People = 5
P(Each) = 1/5

The probability of each cousin is equal in the above scenario i.e. 1/5

Hence, this situation is fair

Situation 4

Numbers = 5 i.e. 2 to 6
P(Prime) = 3/5
P(Composite) = 4/6

The probabilities of prime and composite numbers are not equal.

Hence, this situation is not fair

Situation 5

Roommates = 5
Cards = 5
Aces = 4
P(Each) = 1/5

All probabilities are equal in the above scenario i.e. 1/5

Hence, this situation is fair