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3 years ago

A, B, and Care coplanar. True False

Mathematics

2 answers:

Degger [83]3 years ago

7 0

Answer:

True

Step-by-step explanation:

Co planar means in the same plane

Think of a plane as a big piece of paper going out as far as the eye can see in all directions

ABC are in the same plane

Allushta [10]3 years ago

6 0

B I think hopefully! :)

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In triangle ABC, angle A is 75o and angle B is 20o. Select the triangle that is similar to triangle ABC.

Arturiano [62]

Answer:

A. $\triangle$ DEF where $\angle D = 75^{\circ}$ and $\angle E = 20^{\circ}$ .

Step-by-step explanation:

At first we must keep in mind that two triangles are similar when they have same angle configuration, that is, each pair of angles is congruent. If $\triangle$ ABC and $\triangle$ DEF, then $\angle A \equiv \angle D$ and $\angle B \equiv \angle E$ . Hence, $\angle D = 75^{\circ}$ and $\angle E = 20^{\circ}$ .

In a nutshell, correct answer is A.

4 0

3 years ago

the reptile house at the zoo has 245 reptiles.each habitats hold s 5 reptiles how many habitats are there

Usimov [2.4K]

49 habitats are at the zoo because 245 divided by 5 is 49! (: (: (: hope I helped

6 0

3 years ago

Read 2 more answers

The polynomial of degree 5, P ( x ) has leading coefficient a=1, has roots of multiplicity 2 at x = 3 and x = 0 , and a root of

ser-zykov [4K]

Answer:

$p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}$ , for $r_{1} = 0$

Step-by-step explanation:

The general form of quintic-order polynomial is:

$p_{5}(t) = a\cdot x^{5} + b\cdot x^{4} + c\cdot x^{3} + d\cdot x^{2} + e \cdot x + f$

According to the statement of the problem, the polynomial has the following roots:

$p_{5} (t) = (x - r_{1})\cdot (x-3)^{2}\cdot x^{2} \cdot (x+1)$

Then, some algebraic handling is done to expand the polynomial:

$p_{5} (t) = (x - r_{1}) \cdot (x^{3}-6\cdot x^{2}+9\cdot x) \cdot (x+1)\\p_{5} (t) = (x - r_{1}) \cdot (x^{4}-5\cdot x^{3} + 3 \cdot x^{2} + 9 \cdot x)$

$p_{5} (t) = x^{5} - (5+r_{1})\cdot x^{4} + (3 + 5\cdot r_{1})\cdot x^{3} +(9-3\cdot r_{1})\cdot x^{2} - 9 \cdot r_{1}\cdot x$

If $r_{1} = 0$ , then:

$p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}$

5 0

3 years ago

Would you mind the window ?

kondor19780726 [428]

I don’t know can I ???

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3 years ago

An online company offers a package that includes 2 games for $11.98 they also offer a package that includes 5 games for $24.95 W

Olenka [21]

Answer:

the package that has five games

Step-by-step explanation:

divide both

4.99

and 5.99 4.99 is btter

6 0

3 years ago