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Nesterboy [21]
3 years ago
8

To describe a sequence of transformations that maps triangle ABC onto triangle a"b"c", a student starts with a reflection over t

he x-axis.how should the student complete the sequence of transformations to map triangle ABC onto triangle a"b"c"?
plz help ​

Mathematics
1 answer:
Paha777 [63]3 years ago
8 0

i dont quite get the question but...

i guess this is how it is.

Take the mirror image of∆ABC Through the a line through the point y=3.

The new ∆ABC would have point C=(4,2)

B=(3,-6) A=(1,-3)

Now shifting the ∆ABC one unit (<em>i.e. 2 acc. to the graph as scale is 1 unit =2</em>) towards right ( or <em>adding 2 to the x coordinates of ∆ABC)</em>

We get the Coordinates of triangle ABC as A=(3,-3) B=(5,-6) C=(6,2).

This coordinate is the same coordinates of ∆A"B"C".

Hope it helps...

Regards;

Leukonov/Olegion.

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What binomial do you have to add to the polynomial 2x^2+3y^2-5xy+1 to get the following?
Contact [7]

Binomial -3y^{2}+5xy when added to polynomial 2x^{2} +3y^{2} -5xy+1  gives  polynomial  that does not contain the variable y .

<h3>What is binomial?</h3>

A mathematical expression consisting of two terms connected by a plus sign or minus sign .

Example: x + 2 is a binomial, where x and 2 are two separate terms.

<h3>What is polynomial?</h3>

A polynomial is an expression consisting of indeterminates and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer

According to the question

polynomial 2x^{2} +3y^{2} -5xy+1

when added with  -3y^{2}+5xy  

= 2x^{2}+1   (as 3y^{2} -5xy got cancelled )

that does not contain the variable y

Hence, Binomial -3y^{2}+5xy when added to polynomial 2x^{2} +3y^{2} -5xy+1  gives that does not contain the variable y .

To know more about Binomial and polynomial here :

brainly.com/question/1698358

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Which equation is equivalent to the given equation?<br> x² - 6x = 8
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Harold move no more than 43 of his sheep and goats into another field. fewer than 22 this animals are goats.
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7 = -x+3. Consider the line y = Find the equation of the line that is parallel to this line and passes through the point (-5, 6)
artcher [175]

Answer with explanation:

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→x+y-3=0---------(1)

⇒Equation of line Parallel to Line , ax +by +c=0 is given by, ax + by +K=0.

Equation of Line Parallel to Line 1 is

  x+y+k=0

The Line passes through , (-5,6).

→ -5+6+k=0

→ k+1=0

→k= -1

So, equation of Line Parallel to line 1 is

x+y-1=0

⇒Equation of line Perpendicular  to Line , ax +by +c=0 is given by, bx - a y +K=0.

Equation of Line Perpendicular to Line 1 is

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The Line passes through , (-5,6).

→ -5-6+k=0

→ k-11=0

→k= 11

So, equation of Line Parallel to line 1 is

x-y+11=0

4 0
3 years ago
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