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Alexandra [31]
3 years ago
7

Monitoring the emerald ash borer. The emerald ash borer is a beetle that poses a serious threat to ash trees. Purple traps are o

ften used to detect or monitor populations of this pest. In the counties of your state where the beetle is present, thousands of traps are used to monitor the population. These traps are checked periodically. The distribution of beetle counts per trap is discrete and strongly skewed. A majority of traps have no beetles, and only a few will have more than two beetles. For this exercise, assume that the mean number of beetles trapped is 0.4 with a standard deviation of 0.9.
(a) Suppose that your state does not have the resources to check all the traps, so it plans to check only an SRS of n = 100 traps. What are the mean and standard deviation of the average number of beetles x in 100 traps?
(b) Use the central limit theorem to find the probability that the average number of beetles in 100 traps is greater than 0.5
(c) Do you think it is appropriate in this situation to use the central limit theorem? Explain your answer
Mathematics
1 answer:
Agata [3.3K]3 years ago
4 0

Answer:

B becausde fuhdsdjncd

Step-by-step explanation:

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The mean number of words per minute (WPM) typed by a speed typist is 149149 with a standard deviation of 1414 WPM. What is the p
Semmy [17]

Answer:

The probability is  P(\=  X  >  x ) = 0.78814

Step-by-step explanation:

From the question we are given that

     The population  mean is  \mu  =  149

     The standard deviation is  \sigma  =  14

     The random number    x  =  147.81

      The sample  size is  n  = 88

The probability that  the sample mean would be greater than P(\=  X  >  x ) =  P( \frac{ \= x   -  \mu   }{\sigma_{\= x} }  > \frac{ x - \mu  }{\sigma_{\= x} }  )

Generally the z- score of this normal distribution is mathematically represented as

       Z  =  \frac{ \=  x   -  \mu  }{\sigma_{\= x} }

Now

        \sigma_{\= x } =  \frac{\sigma }{\sqrt{n} }

substituting values

         \sigma_{\= x } =  \frac{14 }{\sqrt{88} }

         \sigma_{\= x } =  1.492

Which implies that

         P(\=  X  >  x ) =  P( Z  > \frac{ 147.81  - 149   }{ 1.492}  )

        P(\=  X  >  x ) =  P( Z  > -0.80  )

Now from the z-table  the  probability is  found to be

        P(\=  X  >  x ) = 0.78814

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Step-by-step explanation:

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Can some help with this problem
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Answer:

20 degrees.

Step-by-step explanation:

The interior angles of a triangle add up to 180 degrees. One of them, bottom right, is already shown as 70 degrees. You can find the bottom left angle by subtracting 110, the supplementary angle, from 180 (the number of degrees in a straight line). The top angle, 2x, is equal to 40 degrees. (180-70-70 = 40). 40/2 = x, so x = 20 degrees.

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