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Contact [7]
3 years ago
7

A compound inequality is graphed and its graph consists of all real numbers. Which of the following could have resulted in this

solution set?
a. r > 3 or r < 2

b. r < 3 or r < 2

c. r > 3 or r > 2

d. r < 3 or r > 2
...?
Mathematics
1 answer:
Feliz [49]3 years ago
4 0
"r < 3 or r > 2" is the one among the following choices given in the question that <span>could have resulted in this solution set. The correct option among all the options that are given in the question is the fourth option or option "d". I hope that this is the answer that has actually come to your desired help.</span>
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There should be 3 more girls than boys in the class (9 boys, 12 girls)
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Read 2 more answers
Which of the following graphs shows a pair of lines that represent the equations with a solution (−5, 2)? (PLEASE HELP ASAP, DUE
gizmo_the_mogwai [7]

Using a system of equations, it is found that the third graph shows a pair of lines that represent the equations with a solution (−5, 2).

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

The solution of the system on a graph is the intersection of two lines. The third graph has an intersection at (-5,2), hence it is the answer to this question.

More can be learned about a system of equations at brainly.com/question/24342899

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5 0
2 years ago
A contractor is building the base of a circular fountain. On the blueprint, the base of the fountain has a diameter of 18 centim
Daniel [21]
The answer is 1808.64 ft²

To calculate area of square we need to find radius r. Radius is a half of a diameter:
r = d/2

The blueprint:
d = 18 cm
r = 18/2 = 9 cm

<span>The blueprint has a scale of three centimeters to four feet. Actual radius r1 is:
</span>3 cm : 4 ft = 18 cm : r1
After crossing the products:
r1 = 4 ft * 18 cm : 3 cm
r1 = 24 ft

The area of the circular base of the fountain is:
A = r1² * π
π = 3.14
r1 = 24 ft

A = 24² * 3.14
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Answer:


Step-by-step explanation:


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