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saveliy_v [14]
3 years ago
6

I have been doing math all day, please help!

Mathematics
2 answers:
Murljashka [212]3 years ago
5 0
Y=-3x+4 is the correct answer
Darya [45]3 years ago
3 0

Answer:

y = -3x + 4

Step-by-step explanation: Substitute the numbers in for x & y to see which one is the answer.

(-1, 7):

y = -3x + 4

7 = -3(-1) + 4

7 = 3 + 4

7 = 7

TRUE


y = 2x - 9

7 = 2(-1) - 9

7 = -2 - 9

7 = -11

FALSE


y = 5x - 2

7 = 5(-1) - 2

7 = -5 - 2

7 = -10

FALSE


y = -3x + 7

7 = -3(-1) + 7

7 = 3 + 7

7 = 10

FALSE


Hope this helps you!!! :)


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What are the lengths?
Montano1993 [528]
In both the figures we have a Right Angled Triangle.

Two sides of the right angled triangles are given and we are to find the Third side. This can be done using the Pythagoras Theorem, which states:

Hypotenuse² = Base² + Perpendicular²

For 1st figure, we have
Base = 21
Perpendicular = 20

So, 

Hypotenuse² = 20² + 21² = 841
⇒
Hypotenuse = 29 (1st option is correct)

For 2nd Image, we have
Base= 6
Hypotenuse = 10

So, we can write:

10² = 6² + Perpendicular²
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⇒
Perpendicular = 8 (Option Fourth)
6 0
3 years ago
Find the zeros of the function.<br> f(x) = 2x2 – 2x – 12
Amiraneli [1.4K]

Answer:

Step-by-step explanation:

2x^2-2x-12

This has solutions of x=3 and x= -2

3 0
3 years ago
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I need help on this question
egoroff_w [7]
25 is the answer hope it helped
8 0
3 years ago
If f(x) = -4x2 - 6x-1 and g(x) = – x2 - 5x + 3, find (f+ g)(x).
ziro4ka [17]

Answer:

- 5x² - 11x + 2

Step-by-step explanation:

(f + g)(x) = f(x) + g(x)

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= - 4x² - 6x - 1 - x² - 5x + 3 ← collect like terms

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4 0
3 years ago
Read 2 more answers
Make q the subject of the formula <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Ba%7D%7Bp%20%7D%20%20-%20%20%5Cfrac%7Bb%7D%7
alukav5142 [94]

Answer:

q=<u>bp</u>

<u> </u><u> </u><u> </u><u> </u>a- cp

Step-by-step explanation:

<u>a</u> - <u>b</u><u> </u>= c

p q

Multiply through by pq

qa - bp = cpq

qa - cpq = bp

q [a-cq] = bp

q= <u>bp</u>

<u> </u><u> </u><u> </u><u> </u><u> </u>a-cp

5 0
3 years ago
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