Answer:
If all you care about is whether you roll 2 or not, you get a Binomial distribution with an individual success probability 1/6. The probability of rolling 2 at least two times, is the same as the probability of not rolling 2 at zero or one time.
the answer is, 1 - bin(k=0, n=4, r=1/6) - bin(k=1, n=4, r=1/6). This evaluates to about 13%, just like your result (you just computed all three outcomes satisfying the proposition rather than the two that didn’t).
Step-by-step explanation:
Answer:
Step-by-step explanation:
1. 3x^1 + 8 - (2x^2 + 1).....distribute the negative thru the parenthesis
3x^1 + 8 - 2x^2 - 1....now combine like terms
-2x^2 + 3x^1 + 7
2. 5x^2 + 3x - 4 - (x^2 - 6x)...same thing..distribute
5x^2 + 3x - 4 - x^2 + 6x...combine like terms
4x^2 + 9x - 4
Answer:
The answer to your question is 4
The sum of twice a number and 6 is 4.
