All categories

2 years ago

100 points !! I need fast help

Mathematics

2 answers:

PolarNik [594]2 years ago

7 0

This is ur required result in attachment

gregori [183]2 years ago

6 0

$QUADRILATERALS \\ \\ Heya \: ! \: \\ \\ \\Check \: the \: attachment. \\ Hope \: \: it \: \: helps \: \: you :)$

You might be interested in

A man drove 14 mi directly east from his home, made a left turn at an intersection, and then traveled 5 mi north to his place of

Stels [109]

Answer:

14.9 miles

Step-by-step explanation:

If the road was created, the 3 different roads would form a right triangle where the new road would be the hypotenuse and the other 2 roads would be the legs.

We can use the pythagorean theorem to find the length of the hypotenuse, or the new road:

a² + b² = c²

14² + 5² = c²

221 = c²

14.9 = c

= 14.9 miles

4 0

2 years ago

X+x+y+y+z+z=24

JulijaS [17]

Answer:

b = 7/2

x = 11/2

y = 21/2

z = -4

Step-by-step explanation:

2x + 2y + 2z = 24

x + y + z = 12

b + 2x + y + z = 21

2b + 2y = 28

b + y = 14

3x + y + z = 23

we can start anywhere by transforming these equations in a way that always one variable is excised by others.

so, e.g.

b = 14 - y

14 - y + 2x + y + z = 21

2x + z = 7

z = 7 - 2x

3x + y + 7 - 2x = 23

x + y = 16

16 + z = 12

z = -4

-4 = 7 - 2x

-11 = -2x

11 = 2x

x = 11/2

11/2 + y = 16

y = 16 - 11/2 = 32/2 - 11/2 = 21/2

b = 14 - 21/2 = 28/2 - 21/2 = 7/2

3 0

1 year ago

Id joom 764 570 0682<br>pc 8aV9Jr

anygoal [31]

Answer:

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Select the graph of the solution set that would represent the following expression. (x-2)=5(x+1)

Lesechka [4]

Answer:

Find the attached

Step-by-step explanation:

We have been given the following expression;

(x-2)=5(x+1)

We are required to determine the graph of the solution set. To do this we formulate the following set of equations;

y = x - 2

y = 5(x+1)

We then graph these two equations on the same cartesian plane. The solution will be the point where these two graphs intersect.

Find the attachment below;

5 0

2 years ago

Read 2 more answers

Which of the following functions are solutions of the differential equation y'' + y = 3 sin x? (select all that apply)

DiKsa [7]

Answer:

Step-by-step explanation:

We must compute the derivatives and check if the equation is satisfied.

A. $y'=(3\sin x)'=3\cos x$ . Differentiate again to get $y''=(3\cos x)'=-3\sin x$ , then $y''+y=-3\sin x+3\sin x=0\neq 3\sin x$ so this choice of y doesn't solve the equation.

B. $y'=3\sin x+3x\cos x-5\cosx +5x\sin x=(5x+3)\sin x+(3x-5)\cos x$ and $y''=5\sin x+(5x+3)\cos x+3\cos x-(3x-5)\sin x=(10-3x)\sin x+(5x+6)\cos x$ , then $y''+y=10\sin x+6\cos x\neq 3\sin x$ so y is not a solution

C. $y'=\frac{-3}{2}\cos x+\frac{3}{2}x\sin x$ hence $y''=\frac{3}{2}\sin x+\frac{3}{2}\sin x+\frac{3}{2}x\cos x=3\sin x+\frac{3}{2}x\cos x$ . Then $y''+y=3\sin x+\frac{3}{2}x\cos x-\frac{3}{2}x\cos x=3\sin x$ so y is a solution.

D. $y'=-3\sin x$ and $y''=-3\cos x$ , then $y''+y=0$ thus y isn't a solution

E. $y'=\frac{3}{2}\sin x+\frac{3}{2}x\cos x$ hence $y''=\frac{3}{2}\cos x+\frac{3}{2}\cos x-\frac{3}{2}x\sin x=3\cos x-\frac{3}{2}x\cos x$ . Then $y''+y=3\cos x-\frac{3}{2}x\cos x-\frac{3}{2}x\cos x=3\cos x\neq 3\sin x$ then y is not a solution.

3 0

2 years ago