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MissTica
3 years ago
7

The path of a roller coaster after it has reached the top of the first hill follows a polynomial function as shown in the graph

below....

Mathematics
2 answers:
Mekhanik [1.2K]3 years ago
6 0
Hello there.

<span>The path of a roller coaster after it has reached the top of the first hill follows a polynomial function as shown in the graph below....

Option A</span>
Paraphin [41]3 years ago
5 0
The interval that f(x) is increasing is the distance from 200 to 300.
The minimum value of f(x) in the interval 0<x<300 is 200.
At a value of 500, the value of f(x) is 0.
The function can't be a quadratic function since there are two points in the graph where f(x) changes its rate from increasing to decreasing or the opposite. A quadratic function has only one of that point.
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Someone help 6th grade math i will give brainliest
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The first one is 64. The second one is -64. Third is 10000
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Answer:

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Step-by-step explanation:

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Mary has planned to save 25% of her weekly earning in savings account. She uses double number line as shown below to determine h
Bas_tet [7]

Answer:

<h2>$175 per week </h2>

Step-by-step explanation:

In this problem we are expected to calculate the amount Mary will save per week based on her 25% plan on her weekly earning of $700

hence we have to calculate 25% of $700 and that will be the answer to the problem

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3 years ago
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3 0
3 years ago
Scientists modeled the intensity of the sun, I, as a function of the number of hours since 6:00 a.m., h, using the
MAVERICK [17]

The functions are illustrations of composite functions.

<em>The soil temperature at 2:00pm is 67</em>

The given parameters are:

\mathbf{I(h) =\frac{12h - h^2}{36}} ---- the function for sun intensity

\mathbf{T(I) =\sqrt{5000I}} -- the function for temperature

At 2:00pm, the value of h (number of hours) is:

\mathbf{h = 2:00pm - 6:00am}

\mathbf{h = 8}

Substitute 8 for h in \mathbf{I(h) =\frac{12h - h^2}{36}}, to calculate the sun intensity

\mathbf{I(8) =\frac{12 \times 8 - 8^2}{36}}

\mathbf{I(8) =\frac{32}{36}}

\mathbf{I(8) =\frac{8}{9}}

Substitute 8/9 for I in \mathbf{T(I) =\sqrt{5000I}}, to calculate the temperature of the soil

\mathbf{T(8/9) =\sqrt{5000 \times 8/9}}

\mathbf{T(8/9) =\sqrt{4444.44}}

\mathbf{T(8/9) =66.67}

Approximate

\mathbf{T(8/9) =67}

Hence, the soil temperature at 2:00pm is 67

Read more about composite functions at:

brainly.com/question/20379727

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2 years ago
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