Answer:
20 meters
Step-by-step explanation:
The track is circular so it means that after Patrick raced the entire track he is back at the starting point. In other words, every 440 meters he is back to the beginning.
So we would have that, if he races round the track twice, he would run 440(2) = 880 meters and he would be back at the starting point.
The problem asks us how far is he from the starting point at the 900 meter mark. If at 880 meters he is at the starting point, then at 900 meters he would be
meters from the starting point.
Answer:
C. (x-2)^2=7
Step-by-step explanation:
What you have to do first is to get rid of the 3 in the x^2 so you will divide 3 by the whole thing to get x^2-4x=3.
You will then divide -4 by 2 and then square the answer to get 4.
You will then add the 4 into the end of the equation and to the 3 to get x^2-4x+4=7.
You will then make into a perfect square (x-2)^2=7 and that is your answer.
<em><u>No</u></em><em><u>,</u></em><em><u> </u></em><em><u>because</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>convert</u></em><em><u> </u></em><em><u>meter</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>millimeter</u></em><em><u> </u></em><em><u>you'll</u></em><em><u> </u></em><em><u>have</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>multiply the length value by 1000</u></em><em><u> </u></em><em><u>which</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>give</u></em><em><u> </u></em><em><u>you</u></em><em><u> </u></em><em><u>3</u></em><em><u>5</u></em><em><u>0</u></em><em><u>0</u></em><em><u>.</u></em>
<em><u>3.5</u></em><em><u> </u></em><em><u>×</u></em><em><u> </u></em><em><u>1</u></em><em><u>0</u></em><em><u>0</u></em><em><u>0</u></em>
<em><u>=</u></em><em><u> </u></em><em><u>3</u></em><em><u>5</u></em><em><u>0</u></em><em><u>0</u></em><em><u>.</u></em>
<em><u>have</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>great</u></em><em><u> </u></em><em><u>day</u></em><em><u>!</u></em>
According to the information given, the ramp would be 50 feet high. (However, that seems really high. Did you type your problem correctly?)
If you draw a picture, you will see that you can set up a cosine ratio to solve this problem. With a 30 degree angle of depression, the angle we are going to use 60 degrees.
We can set up the following equation:
cos(60) = x / 100
0.5 = x / 100
50 = x
Y=x².
This is te function of a parabola open upward
the domain is all values of x ={x/x∈z}