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3 years ago

If (7²)x = 1 what is the vaule of x

Mathematics

2 answers:

IrinaVladis [17]3 years ago

4 0

Answer:

x=4

Step-by-step explanation:

1 Add 11 to both sides.

2x=7+12x=7+1

2 Simplify 7+17+1 to 88.

2x=82x=8

3 Divide both sides by 22.

x=\frac{8}{2}x=

4 Simplify \frac{8}{2}

 to 44.

x=4x=4

cheek:

1 Let x=4x=4.

2\times 4-1=72×4−1=7

2 Simplify 2\times 42×4 to 88.

8-1=78−1=7

3 Simplify 8-18−1 to 77.

7=7 7=7

(or -3)

arsen [322]3 years ago

3 0

Answer:

x=1/49

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation

Add 1 to both sides of the equation :

49x = 1

Divide both sides of the equation by 49:

x = 1/49 = 0.020

Hope this helps....

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The area of the hexagon 24a² -18 is equivalent to 6(4a² -3).

Option A is the correct answer.

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2 years ago

A source of laser light sends rays AB and AC toward two opposite walls of a hall. The light rays strike the walls at points B an

Nataly [62]

Answer:

The distance between the walls is 70 m.

Step-by-step explanation:

Given: A source of laser light is at point A on the ground between two parallel walls BE and CD . The walls are perpendicular to the ground that is

BE ⊥ ED and CD ⊥ ED

AB is a ray of light which strikes the wall on the left at point B which is 30 meters above the ground. that is BE = 30 m

AC is a ray of light which strikes the wall on the right at point C. The length of AC = 80 meters.

The ray AB makes an angle of 45 degrees with the ground that is m∠BAE = 45°

The ray AC makes an angle of 60 degrees with the ground that is m∠CAD = 60°

As shown is figure attached below.

WE have to find the distance between the walls that is Length of ED

Length of ED = EA + AD

Consider the Δ AEB,

Using trigonometric ratio,

$\tan\theta=\frac{perpendicular}{base}$

Here $\theta=45^{\circ}$ , perpendicular = 30 m and base we can find.

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$\tan 45^{\circ}=\frac{30}{EA}$

We know $\tan 45^{\circ}=1$

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Here $\theta=60^{\circ}$ , hypotenuse = 80 m and base we can find.

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We know, $\cos 60^{\circ}=\frac{1}{2}$

thus, Base = 40 m

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Thus, the distance between the walls that is the length of ED = 30 + 40 = 70 m

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