There are two spinners. The first spinner has three equal sectors labeled 1, 2 and 3. The second spinner has four equal sectors
labeled 3, 4, 5 and 6. The spinners are spun once. What is the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner?
HELP PLEASE NEED TO PASS 3 MORE DAYS! GRADUATING!
1) 2
2) 6
3) 9
4) 12
Given that the first spinner has three equal sectors labelled 1, 2 and 3; and the second spinner has equal sectors labelled 3, 4, 5 and 6.
The number of possible outcomes that do not show a 1 on the first spinner is 2 (i.e. the first spinner shows 2 or 3).
The number of possible outcomes that the second spinner show the number 4 is 1 (i.e. the second spinner shows 4)
In probability, the word 'and' goes with multiplication.
Therefore, <span>the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner</span> is given by 2 x 1 = 2 possible outcomes.
i.e. the first spinner shows the number 2 and the second spinner shows the number 4 or the first spinner shows the number 3 and the second spinner shows the number 4.
