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erik [133]
3 years ago
13

There are two spinners. The first spinner has three equal sectors labeled 1, 2 and 3. The second spinner has four equal sectors

labeled 3, 4, 5 and 6. The spinners are spun once.
What is the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner?
HELP PLEASE NEED TO PASS 3 MORE DAYS! GRADUATING!
1) 2
2) 6
3) 9
4) 12
Mathematics
1 answer:
sladkih [1.3K]3 years ago
5 0
Given that the first spinner has three equal sectors labelled 1, 2 and 3; and the second spinner has equal sectors labelled 3, 4, 5 and 6.

The number of possible outcomes that do not show a 1 on the first spinner is 2 (i.e. the first spinner shows 2 or 3).

The number of possible outcomes that the second spinner show the number 4 is 1 (i.e. the second spinner shows 4)

In probability, the word 'and' goes with multiplication.

Therefore, <span>the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner</span> is given by 2 x 1 = 2 possible outcomes.

i.e. the first spinner shows the number 2 and the second spinner shows the number 4 or the first spinner shows the number 3 and the second spinner shows the number 4.
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Is there any choices? I'd either say 3/5 or 60/100.

Step-by-step explanation:

The reason being, both would equal around 60% I believe. 60% is 3/5th's of a 100, and 60/100 is simply 60 out of 100. Unless your going farther than I'm not entirely sure. I'm sorry.

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A dilation with a scale factor of 2 is applied to the three line segments shown. The resulting images are P′Q′¯¯¯¯¯¯¯, A′B′¯¯¯¯¯
ivanzaharov [21]

Answer:

Step-by-step explanation:

Formula to determine the scale factor,

Scale factor = \frac{\text{Dimension of the image}}{\text{Dimension of the original}}

2 = \frac{P'Q'}{PQ}

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P'Q' = 4 cm

Similarly, for the length of A'B',

2 = \frac{A'B'}{AB}

2 = \frac{A'B'}{1.5}

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4 0
3 years ago
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Likurg_2 [28]

Answer: The professor was not accurate with his hypothesis.

Null hypothesis: P1 = 12.5%, P2 = 42.5%, P3 = 45%

The alternate hypothesis: At least one proportion of the student will differ from the others.

Step-by-step explanation: To check if the professors hypothesis were inaccurate.

What percentage of student bought a hard copy of the book.

(25 ÷ 200) × 100 = 12.5%

What percentage of the student printed it from the web.

(85 ÷ 200) × 100 = 42.5%

What percentage of the students read it online.

(90 ÷ 200) × 100 = 45%

This means that the professor was not accurate with his hypothesis. Because the proportion of student in his hypothesis was not the same in the actual.

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