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fomenos
3 years ago
15

Wave Corporation began the current year with a retained earnings balance of $25,000. During the year, the company corrected an e

rror made in the prior year, which was a failure to record depreciation expense of $5,000 on equipment. Also, during the current year, the company earned net income of $15,000 and declared cash dividends of $5,000. Compute the year-end retained earnings balance.
Mathematics
1 answer:
Hitman42 [59]3 years ago
7 0

Answer:

$30,000.

Step-by-step explanation:

Wave Corporation began the current year with a retained earnings balance of $25,000.

Depreciation expense was of $5000

During the current year, the company earned net income of $15,000

Also gave cash dividends of $5,000.

So, year end retained earnings will be :

Year end retained balance = total net income minus net losses and dividends.

25000-5000+15000-5000=30000 dollars

The answer is $30,000.

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In simplest radical form, what are the solutions to the quadratic equation 0 = –3x2 – 4x + 5?
JulsSmile [24]
- 3 x² - 4 x + 5 = 0
x_{1} = \frac{4+ \sqrt{16+60} }{-6} =  \frac{4+8.718}{-6}
x1 = -2.12
x_{2} = \frac{4-8.718}{-6}
x2= 0.786

4 0
3 years ago
What is the equation of a line that passes through the point (8, −2) and is parallel to the line whose equation is 3x + 4y = 15?
Dafna1 [17]

Step 1

<u>Find the slope of the given line</u>

we have

3x+4y=15

Isolate the variable y

Subtract 3x both sides

3x+4y-3x=15-3x

4y=-3x+15

Divide by 4 both sides

y=-\frac{3}{4}x+ \frac{15}{4}

the slope of the given line is

m=-\frac{3}{4}

Step 2

Find the equation of the line that passes through  the point (8,-2) and is parallel to the given line

we know that

if two lines are parallel, then their slopes are equal

The equation of the line into point-slope form is equal to

y-y1=m(x-x1)

we have

m=-\frac{3}{4}

(x1,y1)=(8,-2)

substitute in the equation

y+2=-\frac{3}{4}(x-8)

y=-\frac{3}{4}x+6-2

y=-\frac{3}{4}x+4  or  3x+4y=16

therefore

<u>the answer is</u>

y=-\frac{3}{4}x+4

or

3x+4y=16

8 0
3 years ago
5-p=r-3 multi step equation
const2013 [10]

Answer:

r+p=-8

Step-by-step explanation:

5-p=r-3

5+3-p-r=0

8-p-r=0

r+p=-8

4 0
3 years ago
Let v⃗ 1=⎡⎣⎢033⎤⎦⎥,v⃗ 2=⎡⎣⎢1−10⎤⎦⎥,v⃗ 3=⎡⎣⎢30−3⎤⎦⎥ be eigenvectors of the matrix A which correspond to the eigenvalues λ1=−1, λ2
kaheart [24]

Answer:

- x as a linear combination :

x = -1 v1+ 0 v2+ 1 v3.

- Transpose Ax = (12, -6, -6)

Step-by-step explanation:

Given v1 = (0 3 3),v2 = (1 −1 0), v3 = (3 0 −3) be eigenvectors of the matrix A which correspond to the eigenvalues λ1 = −1, λ2 = 0, and λ3 = 1, respectively, and let x = (−2 −4 0). Express x as a linear combination of v1, v2, and v3, and find Ax .

To write x as a linear combination of v1, v2, and v3

x = -1 v1+ 0 v2+ 1 v3.

To find Ax

Write A = (0 ......3 ......3 )

...................(1 ......-1 ......0)

...................(3 ......0......-3)

Since transpose x = (-2, 4, 0)

Ax =......... (0 ......3......3 )(-2)

...................(1 ......-1 ......0)(4)

...................(3 ......0......-3)(0)

= (0×-2 + 3×4 + 3×0)

...(1×-2 + -1×4 + 0×0)

.. (3×-2 + 0×4 + -3×0)

As = (12)

....(-6)

....(-6)

Transpose Ax = (12, -6, -6)

7 0
3 years ago
If the circumference is 3/2 pi what is the area
11111nata11111 [884]

Here is your answer

\frac{9}{16} \pi \:  {units}^{2}

REASON:

Circumference(C)= 2πr

, where r is radius

Given

C= (3/2) π

So,

2\pi \: r =  \frac{3}{2}\pi

r =   \frac{\frac{3}{2}\pi}{2\pi}

r =  \frac{3}{4}

Now,

area = \pi {r}^{2}

= \pi \times  { (\frac{3}{4}) }^{2}

=  \frac{9}{16}\pi   \: {unit}^{2}

HOPE IT IS USEFUL

8 0
3 years ago
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