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harkovskaia [24]

2 years ago

12

A train travels at a constant speed for one hour and 40 minutes. During this time the train travels 95 miles. If the train conti

nues at the same Constant Speed, which equation models the number of miles,m,It Will travel in t hours?
A)m=5/3t
B)m=3/5t
C)m=31t
D)m=57t

2 answers:

MissTica2 years ago

6 0

The answer is D

Hope this helps

Andreas93 [3]2 years ago

3 0

Answer:

m = 57t, where the units of measurement of 57 are mph and that of t is hr.

Step-by-step explanation:

Use the given info to find the speed of the train, which is a unit rate:

95 miles 95 mi

------------------ = ------------- = 0.95 mile/min

1 hr 40 min 100 min

Better yet, use hours, not minutes.

95 miles 95 mi

------------------ = ------------- = 57 mph

1 hr 40 min 1 2/3 hr

Then m(t) = (rate)(time) = (57 mph)t This corresponds to Answer D.

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Write in slope-intercept form an equation of the line that passes through the points (−1,12) and (1,2).

zzz [600]

Answer:

$y=-5x+7$

Step-by-step explanation:

step 1

Find the slope

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

the points (−1,12) and (1,2)

substitute

$m=\frac{2-12}{1+1}$

$m=\frac{-10}{2}$

$m=-5$

step 2

we know that

The equation of the line in slope intercept form is equl to

$y=mx+b$

where

m is the slope

b is the y-intercept

we have

$m=-5$

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2 years ago

Student records suggest that the population of students spends an average of 6.30 hours per week playing organized sports. The p

Ymorist [56]

Answer:

a) 99.24% chance HLI will find a sample mean between 5.5 and 7.1 hours.

b) 81.64% probability that the sample mean will be between 5.9 and 6.7 hours.

Step-by-step explanation:

To solve this question, it is important to know the Normal probability distribution and the Central Limit Theorem

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

In this problem, we have that:

$\mu = 6.3, \sigma = 2.1, n = 49, s = \frac{2.1}{\sqrt{49}} = 0.3$

A) What is the chance HLI will find a sample mean between 5.5 and 7.1 hours?

This is the pvalue of Z when X = 7.1 subtracted by the pvalue of Z when X = 5.5.

By the Central Limit Theorem, the formula for Z is:

$Z = \frac{X - \mu}{s}$

X = 7.1

$Z = \frac{7.1 - 6.3}{0.3}$

$Z = 2.67$

$Z = 2.67$ has a pvalue of 0.9962

X = 5.5

$Z = \frac{5.5 - 6.3}{0.3}$

$Z = -2.67$

$Z = -2.67$ has a pvalue of 0.0038

So there is a 0.9962 - 0.0038 = 0.9924 = 99.24% chance HLI will find a sample mean between 5.5 and 7.1 hours.

B) Calculate the probability that the sample mean will be between 5.9 and 6.7 hours.

This is the pvalue of Z when X = 6.7 subtracted by the pvalue of Z when X = 5.9

X = 6.7

$Z = \frac{6.7 - 6.3}{0.3}$

$Z = 1.33$

$Z = 1.33$ has a pvalue of 0.9082

X = 5.9

$Z = \frac{5.9 - 6.3}{0.3}$

$Z = -1.33$

$Z = -1.33$ has a pvalue of 0.0918.

So there is a 0.9082 - 0.0918 = 0.8164 = 81.64% probability that the sample mean will be between 5.9 and 6.7 hours.

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lana66690 [7]

Answer:

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bagirrra123 [75]

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