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3 years ago

What's the answer? It's urgent 4^3 divided by 8 - 1 + 5 divided by 8

Mathematics

1 answer:

posledela3 years ago

6 0

Answer:

42.66666667

Step-by-step explanation:

I did it in my calculator

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If 15 women can finish a piece of work in 66 days, how long will 9 women take to finish the work?

Mice21 [21]

Answer:

39.6 Days. It is a proportions problem.

5 0

2 years ago

If there are approximately 1.8 million cars in Vancouver and if each car travels an average of 17,500 kilometres in a year, how

Goryan [66]

Rates are used to measure a quantity over another.

The 1.8 million cars use $1.85 \times 10^{10}$ liters each year

Given

$Cars = 1.8\ million$

$d = 17500km$ --- distance

$r = 40miles/gallon$

First, we calculate the number (n) of gallons used by each car

$r = \frac{d}{n}$

Solve for n

$n = \frac{d}{r}$

So, we have:

$n = \frac{17500km}{40miles/gallon}$

$n = \frac{17500km}{40miles}gallon$

Convert miles to kilometers

$n = \frac{17500km}{40km \times 1.60934}gallon$

$n = \frac{17500km}{64.3738km}gallon$

$n = 271.85\ gallon$

The number of gallons (N), used by all the cars is:

$N = n \times cars$

$N = 271.85 \times 1.8\ million$

$N = 489330000$

Convert to liters

$N = 489330000 \times 3.78541L$

$N = 1852314675.3L$

In scientific notation to 2 decimal places, we have:

$N = 1.85 \times 10^{10}L$

Hence, the number of liters used is $1.85 \times 10^{10}$

Read more about distance and rates at:

brainly.com/question/24659604

4 0

3 years ago

H E L P P P P P P P PP P P P P P P P P P P P PP. PP. P PP P P P P P P P P P P P P P P P P PP P. PP P P P P P P P. P P

Anni [7]

X=69 for the second one

5 0

3 years ago

Read 2 more answers

HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!

castortr0y [4]

Answer:

$3.75

Step-by-step explanation:

dimes= x

quarters= x+2

nickels= 2x+2

sum is 3.75

.10x+.25(x+2)+0.05(2x+2)=3.75

.10x+.25x+.50+0.10x+0.10=3.75

0.45x=3.15

x=7 dimes (0.70)

x+2=9 quarters (2.25)

2x+2=16 nickels (0.80)

They add to $3.75

5 0

2 years ago

Read 2 more answers

A study found that a 95% confidence interval for the mean μ of a particular population was computed from a random sample of 1200

kotykmax [81]

Answer:

95% confidence interval for the mean μ is (6,14)

The Population mean μ lies between ( 6, 14 )

Step-by-step explanation:

Explanation:-

Given random sample 'n' = 1200

95% confidence interval for the mean μ is determined by

$(x^{-} -Z_{\alpha } \frac{S.D}{\sqrt{n} } , x^{-} +Z_{\alpha } \frac{S.D}{\sqrt{n} } )$

Level of significance = 95% 0r 0.05

Z₀.₀₅ = 1.96

$(x^{-} -Z_{\alpha } \frac{S.D}{\sqrt{n} } , x^{-} +Z_{\alpha } \frac{S.D}{\sqrt{n} } )$ = 10 ± 4

Mean of the small sample = 10

95% of confidence intervals are

( 10 ±4 )

( 10 -4 , 10+4)

( 6 , 14 )

95% confidence interval for the mean μ lies between ( 6, 14 )

8 0

2 years ago