1) f(4) = g(4) 2) f(4) = g(–2) 3) f(2) = g(–2) 4) f(–2) = g(

What is the solution to the system of equations below y=-3/4x+3 and y=12.

Alexandra [31]

The correct answer choice is D.

5 0

3 years ago

Match each equation on the left to the mathematical property it uses on the right.

erma4kov [3.2K]

Answer:

The answer to your question is:

Step-by-step explanation:

(4 + 5) + 2 = 4 + (5 + 2) Associative property of addition

2(2x + 4) = 4x + 8 Distributive property

( 7 x ) 3 = 7 (x 3) Associative property of multiplication

( 8 x 2) = (x 8 2) Commutative property of multiplication

( 7 + 3) + 1 = 1 + (7 + 3) Commutative property of addition

6 0

3 years ago

Read 2 more answers

If you have 63 books and you donate 1/3 of you’re books how many will you have left

ryzh [129]

Answer: 42

Step-by-step explanation: you would do 63 divided by 3 then you would get 21 and do 21×2 and get 42

6 0

3 years ago

If b (middle term) is negative and c (last term is positive) then what do you know about the two factors? ex. 2x^2-7x+6

seraphim [82]

Answer:

signs of the constants in the binomial factors are negative

Step-by-step explanation:

Assuming the first term (a) is positive, the fact that c is negative means the constants in the binomial factors have the same sign. The negative b means that sign is negative.

2x^2 -7x +6 = (x -2)(2x -3)

__

Further comment

c is the product of the constants in the binomial factors so will be positive when both those constants have the same sign.

b is the sum of the constants in the binomial factors. If both factors have the same sign (c > 0), then those constants have the same sign as b.

In this analysis, "a" is assumed to be positive. If it is not, then the same analysis can be done after reversing all of the signs.

4 0

3 years ago

1.) What is the equation of the path of firework #1? Write your equation in general form.

valina [46]

1. I'm assumig that the paths are perfect parabolas

this means that their general forms can be written in $y=ax^2+bx+c$

it's easier to find vertex form first then expand to get general form

vertex form is $y=a(x-h)^2+k$ where the vertex is (h,k) and a is a constant

firework #1

vertex is (10,50), so (h,k)=(10,50) and h=10, k=50

$h_1=a(t-10)^2+50$

to find the value of $a$ , subsitute another point

(0,0)

$0=a(0-10)^2+50)$

$0=100a+50$

$a=\frac{-1}{2}$

so the equation in vertex form is $h_1=\frac{-1}{2}(t-10)^2+50$

expand to get general form

$h_1=\frac{-1}{2}(t^2-20t+100)+50$

$h_1=\frac{-1}{2}t^2+10t-50+50$

$h_1=\frac{-1}{2}t^2+10t$

2.

same as last time

vertex is (10,72) so (h,k)=(10,72) so h=10 and k=72

equation is $h_2=a(t-10)^2+72$

find $a$

use another point

(0,22)

$22=a(0-10)^2+72$

$22=100a+72$

$-50=100a$

$a=\frac{-1}{2}$

so the equation in vertex form is $h_2=\frac{-1}{2}(t-10)^2+72$

3.

range is the numbers that h is allowed to be

think about what h represents. it represents the height of the rocket

from the graph, we can see that the lowest possible height is 0yd and the highest height is 50yd

so range is 0 to 50 or 0≤h≤50

domain is the numbers that t is allowed to be

think about what t represents. it represents how long the rocket has been flying

it will stop flying when it hits the ground or at t=20

it starts flying at t=0

so domain is from 0 to 20 or 0≤t≤20

3 0

3 years ago

1) f(4) = g(4) 2) f(4) = g(–2) 3) f(2) = g(–2) 4) f(–2) = g(–2)