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Tema [17]
3 years ago
15

HURRY PLSSSSSS HELPPP

Mathematics
2 answers:
tester [92]3 years ago
6 0

Answer:

a. when there are outliers in the data sets

b. when there are no big gaps in the middle of the data sets

d. when the plots representing the data are nonsymmetrical

Step-by-step explanation:

Jlenok [28]3 years ago
3 0

Answer: its A, B, and D

Step-by-step explanation:

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We will find the solution to the following lhcc recurrence: an=8an−1−16an−2 for n≥2 with initial conditions a0=4,a1=7. The first
bagirrra123 [75]

Answer:

idk try to figure it pouy

Step-by-step explanation:

5 0
3 years ago
What is the interquartile range of the data set ​
Verizon [17]

There are many methods of doing this. This one finds the median; however, instead of halving, you can use quarters instead.

First order the data, ascendingly:

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

Find the median:

For an even number of values: The number of values / 2

For an odd number of values: The number of values + 1 / 2

11 is odd.

11 + 1 / 2

12 / 2 = 6

The median is at the 6th position.

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

The median is 20.

<em>Other method:</em>

<em>You don't need this step.</em>

Using the values lower than the median, exclusive, find the median of the lower values;

For an odd number of values: <u>The number of values + 1 / 2</u>

10, 17, 18, 18, 18

5 + 1 / 2 = 6 / 2 = 3

The median of the lower values is at position 3.

This is the lower quartile.

10, 17, 18, 18, 18

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>The number of values + 1 / 4</em></u>

<em>11 + 1 / 4 = 12 / 4 = 3</em>

<em>10, 17, </em><em>18,</em><em> 18, 18, 20, 20, 25, 25, 30, 30</em>

<em />

Using the values greater than the median, exclusive, find the median:

For an odd number of values: <u>The number of values + 1 / 2</u>

20, 25, 25, 30, 30

5 + 1 / 2 = 6 / 2 = 3

The median of the upper values is at position 3.

20, 25, 25, 30, 30

This is 25.

This is the upper quartile.

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>(The number of values + 1 / 4) * 3</em></u>

<em>(11 + 1 / 4) * 3 = (12 / 4)  * 3 = 3 * 3 = 9</em>

<em>10, 17, 18</em><em>,</em><em> 18, 18, 20, 20, 25, </em><em>25</em><em>, 30, 30</em>

Your interquartile range is 3 - 25

25 - 3 = 21

<h2>21</h2>
8 0
3 years ago
In a group of 50 people 28% of them has flue shots done. What is the probability to choose from this group 15 people that didn't
aliina [53]

Answer:

0.0025 = 0.25%

Step-by-step explanation:

First we need to find how many people don't have flue shots.

28% of 50 is equal to 0.28 * 50 = 14 people.

If 14 people have flue shots, we have 50 - 14 = 36 people that don't have flue shots.

Now, to solve this problem, the probability will be the cases where  we have a group of people that don't have flue shots (that is, a combination of 36 choose 15) over the total cases (combination of 50 choose 15):

C(36,15) / C(50,15) = (36!/15!*21!) / (50!/15!*35!) = 0.0025 = 0.25%

8 0
3 years ago
Equation for= Y=x shift the graph up 5 units
telo118 [61]

Answer:

y = x + 5

Step-by-step explanation:

The graph of the ramp function y = x is a straight line with slope +1 and passing through the origin.  If the whole graph is shifted up 5 units, the equation/function becomes

y = x + 5.  The resulting graph is parallel to y = x.

5 0
3 years ago
A rectangular-prism-shaped toy chest is 2m by 1m by 1m. A shipping crate is packed with 18 of these toy chests. There is no extr
Alika [10]
2*1*1= 2 m^3 per chest

2 m^3 per chest* 18 chests= 36 m^3 total

Final answer: 36 m^3
7 0
3 years ago
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