Answer:
can't be determined
Step-by-step explanation:
we would need to know the total number of bars/chips he brought
The answer would be 9. 9x3=27 and 9x4=36. Although 3 fits into both, 9 is the BIGGER number that also fits into both of the numbers shown in the problem.
3 √10
I think since a^2+b^2=c^2
I think x=8
8/4 = 2
16/2 = 8
The two in the hundredths place is ten times less than the two in the tenths place.