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kozerog [31]
3 years ago
8

Determine whether the given set S is a subspace of the vector space V.A. V is the vector space of all real-valued functions defi

ned on the interval (−[infinity],[infinity]), and S is the subset of V consisting of those functions satisfying f(0)=0.B. V=Mn(R), and S is the subset of all nonsingular matrices.C. V=C3(I), and S is the subset of V consisting of those functions satisfying the differential equation y′′′+7y=x2.D. V=C5(I), and S is the subset of V consisting of those functions satisfying the differential equation y(5)=0.E. V=Pn, and S is the subset of Pn consisting of those polynomials satisfying p(0)=0.F. V=Mn(R), and S is the subset of all upper triangular matrices.G. V=P2, and S is the subset of P2 consisting of all polynomials of the form p(x)=x2+c.

Mathematics
1 answer:
Nataly [62]3 years ago
5 0

Answer:

Check the explanation

Step-by-step explanation:

kindly check the attached image below to Determine whether the given set S is a subspace of the vector space <u><em>(which is contained within a different vector space. So all the subspace is a kind of vector space in their own way, although it is also defined relative to some of the other larger vector space. The linear subspace is more often than not simply called a subspace whenever the situation serves to differentiate it from other types of subspaces.)</em></u> V.A

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Senior class at high school A rented and filled 8 vans and 8 buses with 240 students. High school B rented and filled 4 vans and
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Answer: Each van had 8 students and each bus had 22 students

Step-by-step explanation: We shall start by assigning a letter to represent the unknown variables in this question. Each bus shall be represented by by B while each van shall be represented by V. So if in high school A, 8 vans and 8 buses were filled with 240 students in total, we can derive the expression

8V + 8B = 240. Also if in high school B, 4 vans and 1 bus were filled with 54 students in total, we can as well derive the following expression,

4V + B = 54

What we have at this point is a pair of simultaneous equations with unknown variables V and B

8V + 8B = 240 —————(1)

4V + B = 54 ——————-(2)

From equation (2), we shall make B the subject of the equation. Hence

B = 54 - 4V

We can now substitute for the value of B into equation (1) and equation (1) can now be written as

8V + 8(54 - 4V) = 240

8V + 432 - 32V = 240

By collecting like terms we now have

8V - 32V = 240 - 432

(Note that when a positive value crosses to the other side of an equation it becomes negative and vice versa)

-24V = -192

Divide both sides of the equation by -24

V = 8

That means there 8 students in each van. Now we substitute for the value of V into equation (2)

4V + B = 54

4(8) + B = 54

32 + B = 54

Subtract 32 from both sides of the equation

32 - 32 + B = 54 - 32

B = 22

That means there were 22 students in each bus.

Therefore each van had 8 students and each bus had 22 students

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3 years ago
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Use differentials to approximate the change in cost corresponding to an increase in sales (or production) of one unit. Then comp
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Answer:

dC=3.5

DC is between 3.475 and 3.525

Step-by-step explanation:

So let dx=1 since the change there is a change in 1 unit.

Find dC/dx by differentiating the expression named C.

dC/dx=0.05x+3

So dC=(0.05x+3) dx

Plug in x=10 and dx=1:

dC=(0.05×10+3)(1)

dC=(0.5+3)

dC=3.5

Let D be the change in cost-the triangle thing.

Since dx=1 we only want the change in unit to be within 1 in difference.

So this means we want it to be from x=9 to x=1] ot from x=10 to x=11.

Let's do from x=9 to x=10 first:

DC=C(10)-C(9)

DC=[0.025×10^2+3×10+4]-[0.025×9^2+3×9+4]

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DC=[36.5]-[33.025]

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DC=[0.025×11^2+3×11+4]-[0.025×10^2+3×10+4]

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DC=[3.025+37]-[36.5]

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