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nadya68 [22]
3 years ago
8

How many different 10-letter permutations can be formed from 8 identical H's and two identical T's?

Mathematics
1 answer:
melamori03 [73]3 years ago
4 0

Answer:

<h3>45 different permutations</h3>

Step-by-step explanation:

Given 10 letters with 8 identical H's and two identical T's, the number of different permutations will be expressed as;

= \dfrac{10!}{8!2!}

= \dfrac{10*9*8!}{8!*2!}\\ \\= \dfrac{10*9}{2*1}\\ \\= \dfrac{90}{2}\\ \\= 45

<em>Hence the number of different 10-letter permutations that can be formed from 8 identical H's and two identical T's is 45</em>

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A. Your bed is a rectangle that is 4 feet by 6 feet wide. Draw a model of it below and label the dimensions. Find the perimeter
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The model which model the dimensions of the bed has been attached.

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  • The perimeter of your bed is less than the perimeter of the items, so not all items can be underneath your bed.

<h3>What is the perimeter and area of the bed?</h3>

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Perimeter of the bed = 2(length + width)

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Read more on perimeter of a rectangle:

brainly.com/question/24571594

#SPJ1

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