All categories

4 years ago

6 x (1 + 2)=(_x1)+(_x2) what are the two missing numbers

Mathematics

2 answers:

anzhelika [568]4 years ago

8 0

So to figure this out, we can substitute integers for the blanks, so let's sub in x and y:

6 (1 + 2) = (x) + (2y)

so:

x = 6 + 12 - 2y

x = 18 - 2y

6 (1 + 2) = (18-2y) + (2y)

6 + 12 = 18

18 = 18

So we know that this equation works!

(18 is not the answer but is the result of the equation being proven true)

const2013 [10]4 years ago

5 0

Answer:

Step-by-step explanation:

If you fill it in it fits :)

You might be interested in

Find the equation of a line perpendicular to 4x – 4y = -4 that contains the point (-5, -2).

svetlana [45]

Answer:

Y = -X - 7

Step-by-step explanation:

y-y1 =m(x-x1)

y-(-2)= -1(x-(-5)

y+2 = -1(x+5)

Solve for y

subtract 2 from both sides

y=-x-5-2

Y = -x-7

7 0

3 years ago

Help me pls need help

alexira [117]

Answer:

9s+11

Step-by-step explanation:

Combine like terms → (7s+2s and 2+9 = 9s and 11) and boom

7 0

3 years ago

Read 2 more answers

How do I solve this ?

Andrej [43]

Add the 2 coefficients because they are considered like terms.

Your answer should be 25b to the 4th

3 0

4 years ago

Read 2 more answers

1.Find the slope of the line through (-6, 11) and (15, 20).

GrogVix [38]

Answer:

$\boxed {\boxed {\sf m= \frac{3}{7} }}$

Step-by-step explanation:

We are asked to find the slope of a line. The slope tells us the steepness and direction of a line. It is found by dividing the change in y by the change in x.

$m= \frac{ \Delta y }{\Delta x}$

$m= \frac{y_2-y_1}{x_2-x_1}$

In this formula, (x₁, y₁) and (x₂, y₂) are the points the line passes through. We are given the points (-6, 11) and (15,20). If we match a value with its corresponding variable, we see that: